Math Problem Statement

A local transportation official claims that the mean waiting time at the Bay Bridge toll booth is no more

than 0.40 minutes. 33 randomly selected motorists were surveyed exiting the toll and it was found that

the mean waiting time was 0.46 minutes with a standard deviation of 0.16 minutes. We will test the

official's claim using a 0.01 level of significance.

Solution

To test the claim that the mean waiting time at the Bay Bridge toll booth is no more than 0.40 minutes, we can perform a hypothesis test using the following steps:

Step 1: Set Up Hypotheses

  • Null Hypothesis (H0H_0): μ0.40\mu \leq 0.40 (The mean waiting time is no more than 0.40 minutes)
  • Alternative Hypothesis (HaH_a): μ>0.40\mu > 0.40 (The mean waiting time is greater than 0.40 minutes)

Step 2: Choose Significance Level

The significance level (α\alpha) is given as 0.01.

Step 3: Calculate the Test Statistic

Since the sample size is 33 (which is less than 30) and we do not know the population standard deviation, we will use a t-test.

  1. Sample Mean (xˉ\bar{x}): 0.46 minutes
  2. Sample Standard Deviation (s): 0.16 minutes
  3. Sample Size (n): 33

The formula for the t-test statistic is:

t=xˉμ0s/nt = \frac{\bar{x} - \mu_0}{s / \sqrt{n}}

Where:

  • μ0=0.40\mu_0 = 0.40 (the value stated in the null hypothesis)
  • xˉ=0.46\bar{x} = 0.46
  • s=0.16s = 0.16
  • n=33n = 33

Calculating tt:

t=0.460.400.16/330.060.02772.17t = \frac{0.46 - 0.40}{0.16 / \sqrt{33}} \approx \frac{0.06}{0.0277} \approx 2.17

Step 4: Determine the Critical Value

For a one-tailed t-test at α=0.01\alpha = 0.01 with n1=32n - 1 = 32 degrees of freedom, we can find the critical t-value from t-distribution tables or calculators. The critical t-value for df=32df = 32 at a significance level of 0.01 is approximately 2.457.

Step 5: Decision Rule

  • If the calculated tt is greater than the critical tt, we reject the null hypothesis.

Step 6: Compare and Conclude

  • Calculated tt = 2.17
  • Critical tt = 2.457

Since 2.17<2.4572.17 < 2.457, we do not reject the null hypothesis.

Conclusion

At the 0.01 level of significance, there is not enough evidence to support the claim that the mean waiting time at the Bay Bridge toll booth is greater than 0.40 minutes.

Summary

  1. The official's claim that the mean waiting time is no more than 0.40 minutes is not rejected based on the sample data.
  2. The mean waiting time observed in the sample is 0.46 minutes, but it's not statistically significant at the 0.01 level.

Do you want more details on any part of this analysis or have specific questions? Here are some related questions you might consider:

  1. What assumptions are made in this hypothesis test?
  2. How would the conclusion change with a different significance level?
  3. What are the implications of the test results for the local transportation officials?
  4. How can the sample size affect the power of the test?
  5. What would be the result if the sample mean was 0.39 minutes?

Tip: Always check assumptions of normality and independence before conducting hypothesis tests, especially with smaller sample sizes.

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Math Problem Analysis

Mathematical Concepts

Statistics
Hypothesis Testing
T-Test
Significance Levels

Formulas

t = (x̄ - μ) / (s / √n)

Theorems

Central Limit Theorem
Student's T-Distribution

Suitable Grade Level

Grades 11-12 or College Level