Math Problem Statement

This hyperbola is centered at the origin. Find its equation. Foci: (-9,0) and (9,0) Vertices: (-2,0) and (2,0)

Solution

To find the equation of the hyperbola centered at the origin with the given foci and vertices, follow these steps:

  1. Identify the coordinates of the foci and vertices:

    • Foci: (9,0)(-9,0) and (9,0)(9,0)
    • Vertices: (2,0)(-2,0) and (2,0)(2,0)
  2. Determine the values of cc and aa:

    • The distance from the center to each focus is cc. Here, c=9c = 9.
    • The distance from the center to each vertex is aa. Here, a=2a = 2.
  3. Calculate bb:

    • Use the relationship c2=a2+b2c^2 = a^2 + b^2.
    • Substitute the known values: 92=22+b29^2 = 2^2 + b^2
    • Solve for bb: 81=4+b281 = 4 + b^2 b2=77b^2 = 77 b=77b = \sqrt{77}
  4. Write the standard form of the hyperbola's equation:

    • Since the transverse axis is horizontal, the equation is of the form: x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1
    • Substitute a2a^2 and b2b^2 with the values found: x24y277=1\frac{x^2}{4} - \frac{y^2}{77} = 1

So, the equation of the hyperbola is: x24y277=1\frac{x^2}{4} - \frac{y^2}{77} = 1

Would you like further details or have any questions? Here are some related questions you might find interesting:

  1. How do you find the asymptotes of a hyperbola?
  2. What is the significance of the transverse and conjugate axes in a hyperbola?
  3. How does the orientation of a hyperbola affect its equation?
  4. Can you explain the relationship between the distances in a hyperbola (foci, vertices, and co-vertices)?
  5. How do you graph a hyperbola given its equation?

Tip: Always double-check the distances used for aa, bb, and cc in hyperbola problems to avoid common calculation errors.

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Math Problem Analysis

Mathematical Concepts

Conic Sections
Hyperbolas
Coordinate Geometry

Formulas

Equation of a hyperbola: (x^2 / a^2) - (y^2 / b^2) = 1
Relationship between a, b, and c: c^2 = a^2 + b^2

Theorems

Pythagorean relation for hyperbolas: c^2 = a^2 + b^2

Suitable Grade Level

Grades 10-12