Math Problem Statement

how to find R o R

Solution

To find RRR \circ R (also known as the composition of the relation RR with itself), follow these steps:

What is RRR \circ R?

The composition RRR \circ R of a relation RR on a set AA means applying the relation RR twice. Formally, RRR \circ R is a relation on AA such that: (x,z)RR    yA such that (x,y)R and (y,z)R.(x, z) \in R \circ R \iff \exists y \in A \text{ such that } (x, y) \in R \text{ and } (y, z) \in R. In simple terms, for each pair (x,z)(x, z) in RRR \circ R, there must be some element yAy \in A where:

  1. xx is related to yy, and
  2. yy is related to zz.

Steps to Find RRR \circ R:

  1. List the pairs in RR: Identify all ordered pairs (a,b)(a, b) in RR.
  2. Check the conditions for RRR \circ R: For each pair (x,y)(x, y) in RR, find if there exists another pair (y,z)(y, z) in RR.
  3. Form the new pairs: For each valid pair, create a new pair (x,z)(x, z) that satisfies both conditions.
  4. Collect all new pairs: The set of all such pairs (x,z)(x, z) will be RRR \circ R.

Example:

Let R={(1,2),(2,3),(3,4),(1,3)}R = \{(1, 2), (2, 3), (3, 4), (1, 3)\}.

To find RRR \circ R:

  • Check pairs where the second element of one pair matches the first element of another.
    • From (1,2)(1, 2) and (2,3)(2, 3), we get (1,3)(1, 3).
    • From (1,2)(1, 2) and (2,4)(2, 4), no match.
    • From (2,3)(2, 3) and (3,4)(3, 4), we get (2,4)(2, 4).

Thus, RR={(1,3),(2,4)}R \circ R = \{(1, 3), (2, 4)\}.

Would you like more details on this process or a different example?

Related Questions:

  1. How do you find the inverse of a relation?
  2. What is the difference between the composition of relations and functions?
  3. Can you explain the properties of relation composition?
  4. How does the identity relation interact with composition?
  5. What are some common uses of relation composition in mathematics?

Tip:

When dealing with compositions of relations, drawing a diagram or mapping the elements can make it easier to visualize how the elements are connected.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Set Theory
Relations
Composition of Relations

Formulas

(x, z) ∈ R ∘ R ⇔ ∃ y ∈ A such that (x, y) ∈ R and (y, z) ∈ R

Theorems

-

Suitable Grade Level

Grades 10-12