Math Problem Statement

R1 °R2

R1 = {(1,1) (1,5) (5,1) (5,5) (5,7) (7,5) (7,7)}

R2 = {(1,1) (3,3) (3,5) (5,3) (5,5) (7,7)}

Solution

To compute R1R2R1 \circ R2 (the composition of relations R1R1 and R2R2), we follow these steps:

  1. The composition R1R2R1 \circ R2 is defined as the set of all pairs (a,c)(a, c), where there exists some bb such that (a,b)R2(a, b) \in R2 and (b,c)R1(b, c) \in R1.

    In other words, for each pair (a,b)R2(a, b) \in R2, check if there exists a corresponding pair (b,c)R1(b, c) \in R1. If such a pair exists, then the pair (a,c)(a, c) is part of the composition R1R2R1 \circ R2.

Let's go through the steps to calculate R1R2R1 \circ R2:

  • Look at each element (a,b)(a, b) in R2R2, and check if there's an element (b,c)(b, c) in R1R1.

Elements of R2R2:

  1. (1,1)(1, 1) — In R1R1, we find pairs (1,1)(1, 1) and (1,5)(1, 5), so we add (1,1)(1, 1) and (1,5)(1, 5) to R1R2R1 \circ R2.
  2. (3,3)(3, 3) — There's no corresponding (3,c)(3, c) in R1R1, so no pair is added.
  3. (3,5)(3, 5) — There's no corresponding (5,c)(5, c) in R1R1, so no pair is added.
  4. (5,3)(5, 3) — There's no corresponding (3,c)(3, c) in R1R1, so no pair is added.
  5. (5,5)(5, 5) — In R1R1, we find pairs (5,1)(5, 1), (5,5)(5, 5), and (5,7)(5, 7), so we add (5,1)(5, 1), (5,5)(5, 5), and (5,7)(5, 7) to R1R2R1 \circ R2.
  6. (7,7)(7, 7) — In R1R1, we find (7,5)(7, 5) and (7,7)(7, 7), so we add (7,5)(7, 5) and (7,7)(7, 7) to R1R2R1 \circ R2.

Final result for R1R2R1 \circ R2:

R1R2={(1,1),(1,5),(5,1),(5,5),(5,7),(7,5),(7,7)}R1 \circ R2 = \{ (1, 1), (1, 5), (5, 1), (5, 5), (5, 7), (7, 5), (7, 7) \}

This is the composition of the two relations.

Would you like more details or clarifications? Here are some related questions to deepen your understanding:

  1. How do you interpret the composition of relations geometrically?
  2. Can you explain how relations R1R1 and R2R2 are connected to functions?
  3. What is the difference between the composition of relations and the union of relations?
  4. How would the composition R2R1R2 \circ R1 differ from R1R2R1 \circ R2?
  5. How would you represent these relations and their compositions using matrices?

Tip: In composition of relations, the order matters! So R1R2R1 \circ R2 is not necessarily equal to R2R1R2 \circ R1.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Relation Composition
Discrete Mathematics

Formulas

Composition of Relations: (R1 ∘ R2) = {(a, c) | ∃b ((a, b) ∈ R2 and (b, c) ∈ R1)}

Theorems

Definition of Composition of Relations

Suitable Grade Level

Undergraduate or Advanced High School (Grades 11-12)