Math Problem Statement
Find all points on the graph of the function f(x) = 2 sin(x) + sin2(x) at which the tangent line is horizontal. (Use n as your arbitrary integer.)
Solution
To find all points where the tangent line to the graph of is horizontal, we need to find the values of where the derivative of the function, , equals zero.
Step 1: Differentiate the function
The given function is:
Now, differentiate with respect to :
-
The derivative of is:
-
The derivative of (using the chain rule) is:
Thus, the derivative of is:
Step 2: Set the derivative equal to zero
To find where the tangent line is horizontal, set :
Factor out :
Step 3: Solve for
For this product to equal zero, either or .
Case 1:
The solutions to are: where is any integer.
Case 2:
Solve for : The solutions to are:
Step 4: Combine the solutions
Thus, the points at which the tangent line is horizontal are given by: where .
These are all the -coordinates where the tangent line is horizontal. To find the corresponding points on the graph, substitute these values of into the original function .
Would you like details on finding the actual points on the graph or explanations of any steps?
Here are 5 related questions:
- How do you find the derivative of a trigonometric function?
- What is the significance of the horizontal tangent line on a graph?
- How would you solve other equations involving trigonometric identities?
- Can you find the horizontal tangent points for the function ?
- What is the graphical interpretation of solving ?
Tip: Always check for factoring opportunities when solving equations involving products, as this can simplify solving significantly.
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Math Problem Analysis
Mathematical Concepts
Calculus
Trigonometry
Differentiation
Formulas
f(x) = 2sin(x) + sin^2(x)
f'(x) = 2cos(x) + 2sin(x)cos(x)
cos(x) = 0
1 + sin(x) = 0
Theorems
Derivative of a Function
Chain Rule
Trigonometric Identities
Suitable Grade Level
Grades 11-12
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