Math Problem Statement

what is the horizontal asymptote? y=4x+4/2x^2+12x-12 a)y=1/2 b)none c)y=2 d)y=0

Solution

To determine the horizontal asymptote of the function:

y=4x+42x2+12x12y = \frac{4x + 4}{2x^2 + 12x - 12}

we need to analyze the degrees of the polynomial in the numerator and the denominator.

  1. Degree of the numerator: The highest degree term in the numerator is 4x4x, which has degree 1.
  2. Degree of the denominator: The highest degree term in the denominator is 2x22x^2, which has degree 2.

When the degree of the denominator is greater than the degree of the numerator, the horizontal asymptote is y=0y = 0.

Thus, the correct answer is:

d) y=0y = 0.

Additional Details:

  • When the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is always y=0y = 0.
  • If the degrees were the same, you would divide the leading coefficients to find the horizontal asymptote.

Would you like further clarification or any other questions related to horizontal asymptotes?

Here are some related questions:

  1. What happens to the horizontal asymptote if the degrees of the numerator and denominator are the same?
  2. How do you find the vertical asymptotes of a rational function?
  3. What is the behavior of a rational function at infinity?
  4. How do you graph a rational function based on its asymptotes?
  5. How does the horizontal asymptote relate to limits at infinity?

Tip: Always compare the degrees of the numerator and denominator first to determine if there is a horizontal asymptote.

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Math Problem Analysis

Mathematical Concepts

Rational Functions
Asymptotes
Limits

Formulas

Horizontal Asymptote Rule: If degree of numerator < degree of denominator, asymptote is y = 0

Theorems

Horizontal Asymptote Theorem

Suitable Grade Level

Grades 9-11