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This is a physics problem dealing with momentum conservation. Since the collision involves only the two pucks, and friction is negligible on ice, we can use the principle of conservation of momentum to solve it.

Given:
- Mass of each puck, \( m = 0.15 \, \text{kg} \).
- Initial velocity of puck 1, \( v_{1i} = -14 \, \text{m/s} \) (to the west, so we take it as negative).
- Initial velocity of puck 2, \( v_{2i} = +10 \, \text{m/s} \) (to the east, so we take it as positive).
- Final velocity of puck 1, \( v_{1f} = +10 \, \text{m/s} \) (to the east).

We need to find the final velocity of puck 2, \( v_{2f} \).

### Solution
1. **Initial Momentum**:
   \[
   \text{Initial Momentum} = m \cdot v_{1i} + m \cdot v_{2i} = (0.15 \, \text{kg})(-14 \, \text{m/s}) + (0.15 \, \text{kg})(10 \, \text{m/s})
   \]
   \[
   = -2.1 \, \text{kg m/s} + 1.5 \, \text{kg m/s} = -0.6 \, \text{kg m/s}
   \]

2. **Final Momentum**:
   \[
   \text{Final Momentum} = m \cdot v_{1f} + m \cdot v_{2f} = (0.15 \, \text{kg})(10 \, \text{m/s}) + (0.15 \, \text{kg}) v_{2f}
   \]
   \[
   = 1.5 \, \text{kg m/s} + 0.15 \, \text{kg} \cdot v_{2f}
   \]

3. **Setting Initial Momentum = Final Momentum**:
   \[
   -0.6 \, \text{kg m/s} = 1.5 \, \text{kg m/s} + 0.15 \, \text{kg} \cdot v_{2f}
   \]

4. **Solving for \( v_{2f} \)**:
   \[
   0.15 \, \text{kg} \cdot v_{2f} = -0.6 \, \text{kg m/s} - 1.5 \, \text{kg m/s}
   \]
   \[
   0.15 \, \text{kg} \cdot v_{2f} = -2.1 \, \text{kg m/s}
   \]
   \[
   v_{2f} = \frac{-2.1 \, \text{kg m/s}}{0.15 \, \text{kg}} = -14 \, \text{m/s}
   \]

So, the final velocity of puck 2 is **14 m/s to the west**.

### Answer
The correct answer is:
- **C. 14 m/s west**

Would you like more details or have any questions?

Here are five additional questions to deepen your understanding:
1. How would the answer change if the masses of the pucks were different?
2. What principle allows us to assume momentum is conserved in this collision?
3. How would friction on the ice affect the conservation of momentum?
4. Why do we take directions into account with positive and negative signs?
5. What would happen if both pucks moved in the same direction initially?

**Tip:** Always check the direction of velocities and set a consistent positive or negative convention for calculations in physics problems involving momentum.

Two hockey pucks, each with a mass of 0.15 kg, slide across the ice and collide. Before the collision, puck 1 is moving 14 m/s to the west and puck 2 is moving 10 m/s to the east. After the collision, puck 1 is moving at 10 m/s to the east. What is the velocity of puck 2?

Learn how to find the velocity of a hockey puck after a collision using the conservation of momentum. This physics problem involves calculating the final velocity of puck 2 when given the initial and final velocities of puck 1. Suitable for high school students studying physics.

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