To solve for the final momentum of Object 2 ($p_{2f}$), we can use the principle of conservation of momentum. The total momentum before the collision must equal the total momentum after the collision, assuming there are no external forces.

Step 1: Write the conservation of momentum equation:

$p_{1i} + p_{2i} = p_{1f} + p_{2f}$ Where:

• $p_{1i} = 25 \, \text{kg·m/s}$ (initial momentum of Object 1)
• $p_{2i} = -35 \, \text{kg·m/s}$ (initial momentum of Object 2, negative because it’s moving to the left)
• $p_{1f} = -10 \, \text{kg·m/s}$ (final momentum of Object 1, negative because it's now moving to the left)
• $p_{2f}$ is what we want to find.

Step 2: Solve for $p_{2f}$

Using the conservation of momentum equation: $25 \, \text{kg·m/s} - 35 \, \text{kg·m/s} = -10 \, \text{kg·m/s} + p_{2f}$ Simplifying: $-10 \, \text{kg·m/s} = -10 \, \text{kg·m/s} + p_{2f}$ $p_{2f} = 0 \, \text{kg·m/s}$

Thus, the magnitude of the final momentum of Object 2 is: $\boxed{0 \, \text{kg·m/s}}$ This corresponds to option (c) 0 kg-m/s.

Would you like further explanation or details?

Here are 5 related questions:

1. What conditions must hold true for momentum to be conserved in a collision?
2. What is the difference between elastic and inelastic collisions in terms of momentum and energy?
3. How do we calculate the velocities of objects after a collision from their momentum?
4. In what situations would the final momentum of both objects be zero?
5. How can the impulse-momentum theorem be applied in this scenario?

Tip: Remember that momentum is a vector quantity, so direction is important when solving problems involving collisions.