Math Problem Statement

III. DIRECTION: Read, analyze, and solve the following problems:

  1. A cable hangs in a parabolic arch between two poles that are 800 feet apart. The poles are 40 feet high and the lowest point on the suspended cable is 15 feet above the ground. Find the height of the cable at a point 5 feet from one of the poles. Express your final answer correct to four decimal places.

Solution

To solve the problem, we need to find the height of a cable that forms a parabolic arch between two poles. Here's the step-by-step breakdown:

Step 1: Define the coordinate system and the parabolic equation.

Let’s position the coordinate system such that:

  • The lowest point of the cable is at the origin (0,15)(0, 15) (15 feet above the ground).
  • The poles are 800 feet apart, so their horizontal distance is from x=400x = -400 feet to x=400x = 400 feet.

Since the cable forms a parabola, we assume its equation takes the form:

y=ax2+cy = ax^2 + c

Where:

  • aa is the coefficient we need to determine.
  • c=15c = 15 since the lowest point on the cable is 15 feet above the ground.

Step 2: Use the conditions to determine the value of aa.

The height of the poles is 40 feet, and they are 800 feet apart. Therefore, at x=±400x = \pm 400, the height of the cable y=40y = 40 feet.

Using the equation y=ax2+15y = ax^2 + 15, substitute x=400x = 400 and y=40y = 40:

40=a(400)2+1540 = a(400)^2 + 15 40=160000a+1540 = 160000a + 15 160000a=4015160000a = 40 - 15 160000a=25160000a = 25 a=25160000=0.00015625a = \frac{25}{160000} = 0.00015625

Step 3: Find the height of the cable at a point 5 feet from one of the poles.

If the point is 5 feet from one of the poles, the horizontal distance from the center (lowest point of the cable) is x=4005=395x = 400 - 5 = 395 feet.

Substitute x=395x = 395 into the parabolic equation y=0.00015625x2+15y = 0.00015625x^2 + 15:

y=0.00015625(395)2+15y = 0.00015625(395)^2 + 15 y=0.00015625(156025)+15y = 0.00015625(156025) + 15 y=24.3789+15y = 24.3789 + 15 y=39.3789y = 39.3789

Final Answer:

The height of the cable at a point 5 feet from one of the poles is approximately 39.3789 feet.


Do you want more details or have any questions? Here are five related questions to consider:

  1. What is the height of the cable at the midpoint between the poles?
  2. How does the distance between the poles affect the shape of the parabolic cable?
  3. Can you express the equation of the parabola in vertex form?
  4. What is the slope of the cable at a point 100 feet from the lowest point?
  5. If the cable had a different lowest point, how would that change the equation?

Tip: When dealing with parabolic structures, the vertex form of a parabola (y=a(xh)2+k)(y = a(x-h)^2 + k) is helpful to visualize its geometric properties.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Parabolic Functions

Formulas

Parabola equation: y = ax^2 + c
Substituting known points into the quadratic equation to solve for 'a': y = a(x^2) + c
Vertex form of a parabola: y = a(x-h)^2 + k

Theorems

Properties of parabolas and quadratic equations
Symmetry of parabolic structures

Suitable Grade Level

Grades 10-12