Math Problem Statement

III. DIRECTION: Read, analyze, and solve the following problems:

  1. A cable hangs in a parabolic arch between two poles that are 800 feet apart. The poles are 40 feet high and the lowest point on the suspended cable is 15 feet above the ground. Find the height of the cable at a point 5 feet from one of the poles. Express your final answer correct to four decimal places.

Solution

We are given that a cable hangs in a parabolic shape between two poles that are 800 feet apart. The poles are 40 feet high, and the lowest point of the cable is 15 feet above the ground.

Problem Breakdown:

  • The two poles are 800 feet apart.
  • The cable forms a parabolic shape, so we can represent the cable by a quadratic equation y=ax2+bx+cy = ax^2 + bx + c.
  • The lowest point of the cable is at y=15y = 15 feet (vertex of the parabola).
  • The poles are at x=400x = -400 feet and x=400x = 400 feet, and their height is 40 feet.
  • We are asked to find the height of the cable 5 feet from one of the poles.

Step 1: Define the coordinate system

We will set the origin of our coordinate system at the lowest point of the cable. Hence:

  • The lowest point (vertex) is at (0,15)(0, 15), since the vertex of the parabola is 15 feet above the ground.
  • The two poles are at x=400x = -400 and x=400x = 400, with y=40y = 40.

Step 2: Equation of the parabola

Since the parabola is symmetric and the vertex is at (0,15)(0, 15), we can use the standard form of a parabola: y=a(xh)2+ky = a(x - h)^2 + k where (h,k)(h, k) is the vertex. In this case, h=0h = 0 and k=15k = 15, so the equation becomes: y=ax2+15y = ax^2 + 15

Step 3: Use known points to solve for aa

We know that at x=400x = 400, y=40y = 40 (the height of the poles). Substitute these values into the equation to find aa: 40=a(400)2+1540 = a(400)^2 + 15 40=160000a+1540 = 160000a + 15 25=160000a25 = 160000a a=25160000=16400a = \frac{25}{160000} = \frac{1}{6400}

Step 4: Equation of the cable

Thus, the equation of the cable is: y=16400x2+15y = \frac{1}{6400}x^2 + 15

Step 5: Find the height of the cable 5 feet from one pole

We are asked to find the height at a point 5 feet from one of the poles. Since the poles are at x=400x = 400 and x=400x = -400, we will evaluate the height at x=395x = 395 (which is 5 feet away from x=400x = 400).

Substitute x=395x = 395 into the equation: y=16400(395)2+15y = \frac{1}{6400}(395)^2 + 15 Now, let's calculate the height.

y=16400(156025)+15y = \frac{1}{6400}(156025) + 15 y=1560256400+15y = \frac{156025}{6400} + 15 y=24.3789+15y = 24.3789 + 15 y=39.3789y = 39.3789

Final Answer:

The height of the cable 5 feet from one of the poles is approximately 39.3789 feet.


Do you want any further explanation on these steps? Here are five related questions to consider:

  1. How would the equation change if the poles were a different height?
  2. What if the distance between the poles was increased? How would it affect the parabola?
  3. Can you derive the formula for the height of the cable at any point between the poles?
  4. How would the parabola look if the lowest point of the cable was at ground level (0 feet)?
  5. How would this problem change if the cable didn't form a perfect parabola?

Tip: When solving quadratic problems, always try to find the vertex and symmetry properties to simplify calculations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Parabolas
Coordinate Geometry

Formulas

Standard form of a parabola: y = a(x - h)^2 + k
Substitution to find unknown coefficients
Vertex form of a quadratic equation

Theorems

Properties of parabolas
Symmetry of parabolas

Suitable Grade Level

Grades 9-12