Math Problem Statement

15 23 17 13 3 9 7 6 8 11 16 32 27 4 20 3 28 5 6 11 20 12 8 10 25 10 8 15 11 9 Construct a grouped frequency table with six classes, showing class limit, class boundaries, class midpoints, frequencies, relative frequencies, and cumulative frequencies.

Solution

To create a grouped frequency table with six classes, we'll follow these steps:

Step 1: Organize the Data

First, let's combine and organize all the dataTo create a grouped frequency table with six classes, we'll follow these steps:

Step 1: Organize the Data

First, let's combine and organize all the

Data Set:

15, 23, 17, 13, 3, 9, 7, 6, 8, 11,
16, 32, 27, 4, 20, 3, 28, 5, 6, 11,
20, 12, 8, 10, 25, 10, 8, 15, 11, 9.

Step 2: Determine the Range of Data

  • Minimum value: 3
  • Maximum value: 32

Range = Maximum value - Minimum value = 32 - 3 = 29

Step 3: Determine the Class Width

We will divide the data into 6 classes. To find the class width, we divide the range by the number of classes and round up if necessary.

Class width =RangeNumber of classes=2964.83= \frac{\text{Range}}{\text{Number of classes}} = \frac{29}{6} \approx 4.83

We round this up to 5.

Step 4: Set Class Limits

We will create six classes with width 5, starting from the minimum value 3.

Class LimitsClass BoundariesMidpoint
3 - 72.5 - 7.55
8 - 127.5 - 12.510
13 - 1712.5 - 17.515
18 - 2217.5 - 22.520
23 - 2722.5 - 27.525
28 - 3227.5 - 32.530

Step 5: Calculate Frequencies

Now we will count how many data points fall within each class:

  • Class 3 - 7: 3,3,7,6,6,53, 3, 7, 6, 6, 5 → Frequency = 6
  • Class 8 - 12: ( 9, 8, 11, 11, 10,

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Math Problem Analysis

Mathematical Concepts

Statistics
Grouped Frequency Distribution
Class Intervals

Formulas

Class Width = (Maximum Value - Minimum Value) / Number of Classes
Relative Frequency = Frequency / Total Observations
Cumulative Frequency = Sum of Frequencies up to the Class

Theorems

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Suitable Grade Level

Grades 10-12