Math Problem Statement

The ages of
30 students in a class are given below. Construct a frequency table for grouped data using
6 classes. For convenience, the data has been ordered from smallest to largest.

15, 17, 18, 19, 25, 25, 27, 28, 29, 30, 30, 32, 33, 36, 38, 45, 45, 48, 49, 50, 52, 53, 55, 56, 57, 58, 59, 59, 63, 68

All responses should be whole numbers.

Provide your answer below:

Lower Class Limit Upper Class Limit Frequency $15$ $8$ $41$ $42$ $8$ $68$

Solution

To construct the frequency table for the given data with 6 classes, we can follow these steps:

Step 1: Determine the Range

First, we need to find the range of the data:

  • Maximum Value: 68
  • Minimum Value: 15

Range = Maximum Value − Minimum Value = 68 − 15 = 53.

Step 2: Determine Class Width

Next, divide the range by the number of classes (6). The class width is approximately: Class Width=RangeNumber of Classes=5368.83\text{Class Width} = \frac{\text{Range}}{\text{Number of Classes}} = \frac{53}{6} \approx 8.83 Since the class width must be a whole number, we'll round it up to 9.

Step 3: Create the Classes

Starting from the minimum value (15), we will create 6 classes with a width of 9:

  • Class 1: 15 - 23
  • Class 2: 24 - 32
  • Class 3: 33 - 41
  • Class 4: 42 - 50
  • Class 5: 51 - 59
  • Class 6: 60 - 68

Step 4: Count the Frequencies

Now, we count how many data points fall into each class:

  • Class 1 (15 - 23): 15, 17, 18, 19 → Frequency = 4
  • Class 2 (24 - 32): 25, 25, 27, 28, 29, 30, 30, 32 → Frequency = 8
  • Class 3 (33 - 41): 33, 36, 38 → Frequency = 3
  • Class 4 (42 - 50): 45, 45, 48, 49, 50 → Frequency = 5
  • Class 5 (51 - 59): 52, 53, 55, 56, 57, 58, 59, 59 → Frequency = 8
  • Class 6 (60 - 68): 63, 68 → Frequency = 2

Step 5: Construct the Table

Lower Class LimitUpper Class LimitFrequency
15234
24328
33413
42505
51598
60682

Answer:

The frequency table for the given data is as follows:

Lower Class LimitUpper Class LimitFrequency
15234
24328
33413
42505
51598
60682

Would you like further details or assistance with other aspects of this problem?

Here are some related questions for practice:

  1. How would the frequency table change if we used a class width of 8 instead of 9?
  2. What is the cumulative frequency for each class in the above table?
  3. How do you determine the class boundaries for this frequency table?
  4. How can you visualize this data using a histogram?
  5. What is the mean age of the students based on the frequency table?

Tip: When constructing a frequency table, always round the class width to a convenient number that ensures all data points are included in the ranges.

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Math Problem Analysis

Mathematical Concepts

Statistics
Frequency Table
Grouped Data

Formulas

Class Width = Range / Number of Classes
Frequency Table Construction

Theorems

Range Calculation
Class Interval Construction

Suitable Grade Level

Grades 8-10