Here is the graph of the function $f(x) = -2(x - 1)^2 + 2$, showing its key points:

• The vertex is at $(1, 2)$, marked at the top of the parabola.
• The y-intercept is at $(0, 0)$.
• The function is symmetric about the axis of symmetry $x = 1$, indicated by the dashed green line.
• The parabola opens downward because the coefficient of $(x - 1)^2$ is negative, and it is vertically stretched due to the factor of -2.

Would you like more details or have any other questions?

Here are 5 related questions you could explore:

1. How does changing the value of $a$ affect the width of the parabola?
2. What happens if the vertex of the parabola is moved to a different point?
3. How do you find the x-intercepts of a parabola, if they exist?
4. What role does symmetry play in the graph of a quadratic function?
5. How would the graph change if the equation were $f(x) = 2(x - 1)^2 + 2$?

Tip: The vertex form of a quadratic equation provides an easy way to read the vertex and direction of the parabola directly from the equation.