Math Problem Statement

Graph the function N= 778/1+5e^-0.02t

Solution

Here is the graph of the function N(t)=7781+5e0.02tN(t) = \frac{778}{1 + 5e^{-0.02t}}. It shows how NN changes over time, approaching a limiting value as tt increases.

Would you like more details on this function, such as its properties or asymptotic behavior?

Here are some related questions for further exploration:

  1. What is the long-term behavior of the function as tt approaches infinity?
  2. How does the value of kk affect the shape and asymptote of the graph?
  3. Can we find the initial growth rate of NN when t=0t = 0?
  4. How does modifying the constant rr change the growth rate?
  5. How would the function change if the exponent's sign were reversed?

Tip: The horizontal asymptote of such logistic-like functions can often be found by evaluating the function as tt goes to infinity.

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Logistic Functions
Asymptotic Behavior
Graphing Functions

Formulas

N(t) = 778 / (1 + 5e^(-0.02t))

Theorems

Asymptotic behavior of exponential functions
Limit behavior of logistic functions

Suitable Grade Level

Grades 11-12