https://file.aiquickdraw.com/mathbot/file/1727627024708c7c372nm.jpg

The equation given in the image is in slope-intercept form:

\[
y = -\frac{8}{3}x + 3
\]

This equation follows the form \(y = mx + b\), where:
- \(m\) is the slope of the line (here, \(m = -\frac{8}{3}\)),
- \(b\) is the y-intercept (here, \(b = 3\)).

### Step-by-step Graphing Instructions:
1. **Plot the y-intercept**: The y-intercept is \(b = 3\). So, plot a point at (0, 3) on the y-axis.
   
2. **Use the slope**: The slope is \(-\frac{8}{3}\), meaning for every 3 units you move to the right along the x-axis, move 8 units down (since the slope is negative). From the point (0, 3), move:
   - 3 units to the right (positive direction on the x-axis),
   - 8 units down (since the slope is negative).

   This leads to the point (3, -5).

3. **Draw the line**: Now, connect the two points (0, 3) and (3, -5) with a straight line.

The graph should show a downward sloping line passing through these points.

Let me know if you'd like to see the graph or need more details!

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Here are five related questions:
1. How do you find the slope from two points on a line?
2. What is the significance of the y-intercept in real-life problems?
3. How would you graph a line with a positive slope?
4. What happens to the graph if the slope becomes zero?
5. How do you convert from standard form to slope-intercept form?

**Tip**: When plotting lines, always remember to check the scale on both the x and y axes to ensure accuracy.

Use the slope-intercept form to graph the equation y = -8/3x + 3. Use the graphing tool to graph the line.

Learn how to graph the linear equation y = -8/3x + 3 using slope-intercept form. This problem demonstrates key algebraic concepts, including identifying the slope (-8/3) and y-intercept (3), and how to graph the line using these points. Suitable for Grades 8-10.

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