The equation you provided is in slope-intercept form, which is:

$y = mx + b$

Where:

• $m$ is the slope,
• $b$ is the y-intercept (the point where the line crosses the y-axis).

For your equation $y = \frac{2}{3}x - 4$:

• The slope $m = \frac{2}{3}$, meaning for every 3 units moved horizontally (along the x-axis), the line rises by 2 units vertically.
• The y-intercept $b = -4$, meaning the line crosses the y-axis at the point $(0, -4)$.

Graphing the line:

1. Start by plotting the y-intercept $(0, -4)$.
2. Use the slope to find another point. From $(0, -4)$, move 3 units to the right (along the x-axis) and 2 units up (since the slope is positive). This will give the point $(3, -2)$.
3. Draw a straight line through these two points.

Would you like more details or any further clarifications?

Here are 5 related questions you might consider:

1. How do you determine the slope from a graph?
2. What happens to the graph if the slope changes to a negative value?
3. How do you find the x-intercept from this equation?
4. What is the general form of a linear equation, and how does it compare to the slope-intercept form?
5. How do parallel lines relate to the slopes of their equations?

Tip: When the slope is a fraction, it indicates a ratio between the rise (change in y) and the run (change in x).