Math Problem Statement

Graph this line: y–2= 1/3 (x+5)

Solution

Let's start by analyzing the given equation and converting it into a more usable form.

The equation is:

y2=13(x+5)y - 2 = \frac{1}{3}(x + 5)

Step 1: Simplify the equation

Distribute the 13\frac{1}{3} on the right side:

y2=13x+53y - 2 = \frac{1}{3}x + \frac{5}{3}

Step 2: Solve for yy

Add 2 to both sides to isolate yy:

y=13x+53+2y = \frac{1}{3}x + \frac{5}{3} + 2

Now, convert 22 to 63\frac{6}{3} to add it to 53\frac{5}{3}:

y=13x+53+63y = \frac{1}{3}x + \frac{5}{3} + \frac{6}{3}

y=13x+113y = \frac{1}{3}x + \frac{11}{3}

So, the equation of the line is:

y=13x+113y = \frac{1}{3}x + \frac{11}{3}

Step 3: Graph the line

To graph this, let's identify the slope and y-intercept:

  • Slope: 13\frac{1}{3} (which means for every 3 units you move horizontally, the line moves 1 unit up).
  • Y-intercept: 113\frac{11}{3} or approximately 3.67.

Plotting:

  1. Start at the y-intercept (0,113)\left(0, \frac{11}{3}\right), which is roughly (0,3.67)(0, 3.67).
  2. From there, use the slope 13\frac{1}{3} to move 3 units to the right and 1 unit up to plot the next point.
  3. Repeat the process in both directions to complete the line.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Slope-Intercept Form
Graphing

Formulas

y = mx + b

Theorems

Slope formula

Suitable Grade Level

Grades 7-9