In this problem, you're asked to reflect the triangle $\triangle PQR$ over the y-axis. To perform a reflection over the y-axis, you reverse the sign of the x-coordinates of each vertex, while keeping the y-coordinates unchanged.

Here are the current coordinates of the triangle's vertices:

• $P(-8, 2)$
• $Q(-4, -2)$
• $R(-6, -4)$

Now, let's reflect them over the y-axis:

• The reflection of $P(-8, 2)$ is $P'(8, 2)$.
• The reflection of $Q(-4, -2)$ is $Q'(4, -2)$.
• The reflection of $R(-6, -4)$ is $R'(6, -4)$.

Now, plot the reflected points $P'(8, 2)$, $Q'(4, -2)$, and $R'(6, -4)$ on the graph. Connect the points to form the new triangle $\triangle P'Q'R'$.

Would you like more details or have any questions?

Here are five related questions to explore:

1. What changes occur when reflecting a shape over the x-axis instead?
2. How do you find the reflection of a point over the origin?
3. What are the rules for reflecting over lines other than the x- or y-axis (e.g., $y = x$)?
4. What happens to the area of a triangle when it is reflected?
5. How can you verify the accuracy of your reflection?

Tip: When reflecting across an axis, remember that the axis acts like a "mirror," so the distance from the point to the axis should be preserved, but the direction changes.