Math Problem Statement

Given \( \triangle PQR \) with vertices \( P(5,1) \), \( Q(2,2) \), and \( R(3,4) \), write the translation equivalent to the composition of transformations \( r_b \circ r_{x\text{-axis}} \), where \( b \) is the line \( y = 8 \).

Solution

To solve this problem, let's break down each component step-by-step.

Problem Analysis

We are given:

  1. Triangle PQR with vertices P(5,1)P(5,1), Q(2,2)Q(2,2), and R(3,4)R(3,4).
  2. Two transformations:
    • rbr_{b}: Reflection over the line y=8y = 8.
    • rx-axisr_{x\text{-axis}}: Reflection over the x-axis.

We need to find a translation that is equivalent to the composition of these transformations, rbrx-axisr_{b} \circ r_{x\text{-axis}}, and express it in terms of a translation TT that maps PQR\triangle PQR accordingly.

Step-by-Step Solution

  1. Reflect over the x-axis:

    • Reflecting over the x-axis changes the yy-coordinates of the points to their negatives.
    • Thus:
      • P(5,1)P(5,1)P(5,1) \rightarrow P'(5,-1)
      • Q(2,2)Q(2,2)Q(2,2) \rightarrow Q'(2,-2)
      • R(3,4)R(3,4)R(3,4) \rightarrow R'(3,-4)
  2. Reflect over the line y=8y = 8:

    • To reflect over the line y=8y = 8, calculate the new positions of PP', QQ', and RR' by using the fact that the reflection of a point (x,y)(x, y) over the line y=8y = 8 will be (x,16y)(x, 16 - y).
    • Applying this:
      • P(5,1)P(5,16(1))=P(5,17)P'(5, -1) \rightarrow P''(5, 16 - (-1)) = P''(5, 17)
      • Q(2,2)Q(2,16(2))=Q(2,18)Q'(2, -2) \rightarrow Q''(2, 16 - (-2)) = Q''(2, 18)
      • R(3,4)R(3,16(4))=R(3,20)R'(3, -4) \rightarrow R''(3, 16 - (-4)) = R''(3, 20)
  3. Determine the Translation:

    • Now we compare the original points P(5,1)P(5,1), Q(2,2)Q(2,2), and R(3,4)R(3,4) with the final points P(5,17)P''(5,17), Q(2,18)Q''(2,18), and R(3,20)R''(3,20).
    • Observing the change:
      • PP moved from (5,1)(5,1) to (5,17)(5,17), a vertical shift of +16+16.
      • QQ moved from (2,2)(2,2) to (2,18)(2,18), a vertical shift of +16+16.
      • RR moved from (3,4)(3,4) to (3,20)(3,20), a vertical shift of +16+16.

    Therefore, the translation that is equivalent to the composition of these reflections is a vertical translation of 16 units.

Final Answer

The equivalent translation TT is: T(0,16)T(0, 16)

Would you like further details or have any questions?


Here are some related questions that could extend your understanding:

  1. How would the equivalent translation change if the line bb was at y=10y = 10?
  2. What would happen if the reflection sequence was reversed, i.e., rx-axisrbr_{x\text{-axis}} \circ r_{b}?
  3. How can you generalize the translation vector for any line y=cy = c instead of y=8y = 8?
  4. What are other types of transformations that are equivalent to compositions of reflections?
  5. How can this method be applied in 3D geometry?

Tip: Reflections over lines other than the axes can often be converted into translations when combined with additional reflections.

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Math Problem Analysis

Mathematical Concepts

Transformation Geometry
Reflections
Translations

Formulas

Translation formula: T(x, y) = (x + a, y + b)
Reflection over a line formula

Theorems

Composition of Reflections
Transformation Equivalence Theorem

Suitable Grade Level

Grades 10-12