Math Problem Statement

Graph y = -x2 + 7 domain range y x int

Solution

Let's analyze the function y=x2+7y = -x^2 + 7 step by step and determine its domain, range, x-intercepts, and y-intercept.

1. Domain:

The domain of a quadratic function is the set of all possible x-values. Since this is a basic quadratic function, there are no restrictions on xx. Therefore, the domain is:

Domain=(,)\text{Domain} = (-\infty, \infty)

2. Range:

The range of a quadratic function depends on its vertex and whether it opens upwards or downwards. Since the coefficient of x2x^2 is negative (1-1), the parabola opens downwards, and the maximum value is at the vertex.

To find the vertex, we use the formula for the x-coordinate of the vertex in a quadratic function, x=b2ax = -\frac{b}{2a}. In the equation y=x2+7y = -x^2 + 7, we have a=1a = -1 and b=0b = 0, so the x-coordinate of the vertex is:

x=02(1)=0x = -\frac{0}{2(-1)} = 0

Substituting x=0x = 0 into the equation for yy, we get the y-coordinate of the vertex:

y=(0)2+7=7y = -(0)^2 + 7 = 7

Since the parabola opens downwards, the maximum value of yy is 7, and the range is:

Range=(,7]\text{Range} = (-\infty, 7]

3. y-intercept:

To find the y-intercept, set x=0x = 0 and solve for yy:

y=(0)2+7=7y = -(0)^2 + 7 = 7

So, the y-intercept is (0,7)(0, 7).

4. x-intercepts:

To find the x-intercepts, set y=0y = 0 and solve for xx:

0=x2+70 = -x^2 + 7 x2=7x^2 = 7 x=±7x = \pm \sqrt{7}

So, the x-intercepts are (7,0)(\sqrt{7}, 0) and (7,0)(-\sqrt{7}, 0), which are approximately (2.65,0)(2.65, 0) and (2.65,0)(-2.65, 0).

Graph:

The graph is a downward-opening parabola with vertex (0,7)(0, 7), and it crosses the x-axis at approximately x=2.65x = 2.65 and x=2.65x = -2.65.

Would you like a detailed graph of this function?

Relative Questions:

  1. How does the vertex form of a quadratic equation help in graphing?
  2. Why does the parabola open downwards in this equation?
  3. How can you find the x-intercepts for any quadratic function?
  4. What happens to the range of a parabola if the parabola opens upwards?
  5. What would be the effect of shifting this parabola vertically by 3 units?

Tip:

To graph any quadratic function, finding the vertex and intercepts gives you key points that make sketching the graph easier.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Graphing Parabolas
Domain and Range

Formulas

y = ax^2 + bx + c (Standard form of a quadratic function)
x = -b/2a (Vertex formula)
x-intercept calculation: Set y = 0

Theorems

Quadratic Function Theorem: The graph of a quadratic function is a parabola.
Vertex Theorem: The vertex of a parabola is the point (h, k) where h = -b/2a.

Suitable Grade Level

Grades 9-10