Math Problem Statement

41

Find the minimum or maximum value of the function y = -x^2 - 4x - 2. Describe the domain and range of the function, and where the function is increasing and decreasing.

Solution

The problem in question asks for several things regarding the function:

  • Find the minimum or maximum value of the function.
  • Describe the domain and range of the function.
  • Determine where the function is increasing and decreasing.

Let’s go over problem 41, where the function is:

y=x24x2y = -x^2 - 4x - 2

1. Find the Minimum or Maximum Value of the Function

This is a quadratic function in the form y=ax2+bx+cy = ax^2 + bx + c, where a=1a = -1, b=4b = -4, and c=2c = -2.

Since a=1a = -1 (negative), the parabola opens downward, meaning the function has a maximum value.

To find the maximum value, use the vertex formula for the x-coordinate of the vertex: x=b2a=(4)2(1)=42=2x = \frac{-b}{2a} = \frac{-(-4)}{2(-1)} = \frac{4}{-2} = -2

Now, substitute x=2x = -2 into the function to find the y-coordinate of the vertex (the maximum value): y=(2)24(2)2=4+82=2y = -(-2)^2 - 4(-2) - 2 = -4 + 8 - 2 = 2 So, the maximum value is 2.

2. Describe the Domain and Range

  • The domain of any quadratic function is all real numbers: R\mathbb{R}, or (,)(- \infty, \infty).
  • The range depends on whether the parabola opens up or down. Since the parabola opens downward and has a maximum value of 2, the range is: (,2](-\infty, 2]

3. Determine Where the Function is Increasing and Decreasing

For a parabola opening downward:

  • The function is increasing on the interval to the left of the vertex, (,2)(-\infty, -2).
  • The function is decreasing on the interval to the right of the vertex, (2,)(-2, \infty).

Summary of Key Points:

  • Maximum value: 2 (occurs at x=2x = -2).
  • Domain: (,)(- \infty, \infty)
  • Range: (,2](- \infty, 2]
  • Increasing: (,2)(-\infty, -2)
  • Decreasing: (2,)(-2, \infty)

Would you like more details on any specific part of this solution?
Here are some related questions for further practice:

  1. How do you find the vertex of a quadratic function?
  2. What is the significance of the sign of the leading coefficient in determining the direction of a parabola?
  3. How do you determine if a quadratic function has a minimum or maximum value?
  4. Can you explain the relationship between the vertex and the intervals of increase/decrease for a parabola?
  5. How do we define the domain and range for any quadratic function?

Tip: The vertex of a parabola provides both the maximum or minimum value and splits the graph into increasing and decreasing intervals.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Maxima and Minima
Intervals of Increase and Decrease

Formulas

Vertex of a parabola: x = -b / 2a
Quadratic equation formula: y = ax^2 + bx + c

Theorems

The sign of the leading coefficient (a) determines whether a parabola opens upward or downward
The vertex provides the maximum or minimum value

Suitable Grade Level

Grades 9-11