The image shows a parallelogram $PQRS$ plotted on a coordinate grid. You are tasked with rotating this parallelogram 90° counterclockwise around the origin.

To perform a 90° counterclockwise rotation:

For a point $(x, y)$, the new coordinates after a 90° counterclockwise rotation are given by $(-y, x)$.

Step-by-step process:

1. Identify the original coordinates of the points $P, Q, R, S$:

   • $P(-8, 2)$
   • $Q(-6, 0)$
   • $R(-2, 2)$
   • $S(-4, 4)$

2. Apply the rotation formula $(x, y) \rightarrow (-y, x)$:

   • For $P(-8, 2)$, the new coordinates are $(-2, -8)$.
   • For $Q(-6, 0)$, the new coordinates are $(0, -6)$.
   • For $R(-2, 2)$, the new coordinates are $(-2, -2)$.
   • For $S(-4, 4)$, the new coordinates are $(-4, -4)$.

3. Plot the new points $P', Q', R', S'$ on the grid:

   • $P'(-2, -8)$
   • $Q'(0, -6)$
   • $R'(-2, -2)$
   • $S'(-4, -4)$

After plotting these points, you can connect them to form the rotated parallelogram $P'Q'R'S'$.

Would you like me to generate a visual of the rotated parallelogram or explain any part further?

Here are some related questions to extend your learning:

1. What is the general rule for rotating a point 180° around the origin?
2. How would you rotate a point 90° clockwise instead of counterclockwise?
3. How can you determine if a shape is symmetric after a rotation?
4. What transformations preserve the area of a shape?
5. How can reflections differ from rotations in their effect on a shape?

Tip: Always remember that for a 90° counterclockwise rotation, the rule $(x, y) \rightarrow (-y, x)$ holds, and for clockwise, it's $(x, y) \rightarrow (y, -x)$.