You are asked to graph the line given by the equation:

$y = -5x + 8$

This equation is in slope-intercept form, $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

1. Y-Intercept: The y-intercept $b = 8$ means the line crosses the y-axis at $(0, 8)$.

2. Slope: The slope $m = -5$ means for every 1 unit increase in $x$, $y$ decreases by 5 units (a steep negative slope).

Steps to Graph:

1. Start at the y-intercept: plot the point $(0, 8)$.
2. Use the slope $-5$ to find another point. From $(0, 8)$, move 1 unit to the right (increase $x$ by 1), then 5 units down (decrease $y$ by 5). This gives you the point $(1, 3)$.
3. Plot the point $(1, 3)$ and draw a straight line through these two points.

Would you like more details or help with the graphing?

Here are some related questions you might consider:

1. What is the effect of changing the slope on the steepness of the line?
2. How do you graph lines with fractional slopes?
3. How would the graph change if the y-intercept was negative?
4. How can we determine if two lines are parallel or perpendicular using their slopes?
5. What are the steps to convert a general linear equation to slope-intercept form?

Tip: When graphing a line, always check at least two points to ensure accuracy.