The slope-intercept form of a line's equation is given by:

$y = mx + b$

where:

• $m$ is the slope
• $b$ is the y-intercept

Given:

• Slope $m = 8$
• Y-intercept $b = -5$

Substituting these values:

$y = 8x - 5$

This is the required equation of the line in slope-intercept form.

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Related Questions:

1. How do you find the slope of a line given two points?
2. Convert $y = 8x - 5$ into standard form.
3. Find the x-intercept of the line $y = 8x - 5$.
4. What is the equation of a line parallel to $y = 8x - 5$ and passing through (2,3)?
5. What is the equation of a line perpendicular to $y = 8x - 5$ and passing through (1,-2)?

Tip: The slope of a line perpendicular to another line is the negative reciprocal of the original slope.