Math Problem Statement
Draw a graph to match the description given.
f(x) has a
negative
derivative over
left parenthesis negative infinity comma negative 5 right parenthesis
and
left parenthesis 3 comma infinity right parenthesis
and a
positive
derivative over
left parenthesis negative 5 comma 3 right parenthesis
,
and
f prime
(negative 5)equals
0,
but
f prime
(3
)
does not exist.
Solution
Here’s a graph that illustrates the function based on the conditions provided:
- The function decreases on , reaching a minimum at .
- It increases from to .
- At , there’s a cusp, and the function starts decreasing again for .
Would you like a detailed explanation of any of the sections or have any specific questions?
Here are related questions to deepen your understanding:
- What types of critical points are commonly seen on graphs, and how do they affect the shape?
- How can you determine the existence of a cusp or vertical tangent based on the derivative?
- Why does a sign change in the derivative indicate increasing or decreasing behavior?
- What are examples of functions with cusps and vertical tangents?
- How can you approximate the graph of a derivative based on the original function?
Tip: To identify critical points and behavior changes, analyze where the derivative equals zero or is undefined.
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Math Problem Analysis
Mathematical Concepts
Calculus
Derivative Analysis
Increasing and Decreasing Intervals
Critical Points
Cusps and Vertical Tangents
Formulas
f'(x) > 0 indicates increasing intervals
f'(x) < 0 indicates decreasing intervals
Theorems
First Derivative Test
Critical Points and Cusp Formation
Suitable Grade Level
Grades 11-12
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