Math Problem Statement

Draw a graph to match the description given.

​f(x) has a

negative

derivative over

left parenthesis negative infinity comma negative 5 right parenthesis

and

left parenthesis 3 comma infinity right parenthesis

and a

positive

derivative over

left parenthesis negative 5 comma 3 right parenthesis

​,

and

f prime

​(negative 5​)equals

​0,

but

f prime

​(3

​)

does not exist.

Solution

Here’s a graph that illustrates the function f(x)f(x) based on the conditions provided:

  • The function decreases on (,5)(-\infty, -5), reaching a minimum at x=5x = -5.
  • It increases from x=5x = -5 to x=3x = 3.
  • At x=3x = 3, there’s a cusp, and the function starts decreasing again for x>3x > 3.

Would you like a detailed explanation of any of the sections or have any specific questions?


Here are related questions to deepen your understanding:

  1. What types of critical points are commonly seen on graphs, and how do they affect the shape?
  2. How can you determine the existence of a cusp or vertical tangent based on the derivative?
  3. Why does a sign change in the derivative indicate increasing or decreasing behavior?
  4. What are examples of functions with cusps and vertical tangents?
  5. How can you approximate the graph of a derivative based on the original function?

Tip: To identify critical points and behavior changes, analyze where the derivative equals zero or is undefined.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivative Analysis
Increasing and Decreasing Intervals
Critical Points
Cusps and Vertical Tangents

Formulas

f'(x) > 0 indicates increasing intervals
f'(x) < 0 indicates decreasing intervals

Theorems

First Derivative Test
Critical Points and Cusp Formation

Suitable Grade Level

Grades 11-12