Math Problem Statement

In the given figure, if DE || BC, ∠ABC = 118°, ∠DAB = 42°, then ∠ADE is equal to?

Solution

To solve the given problem, we need to determine ADE\angle ADE based on the provided information:

Given Information:

  1. DEBCDE \parallel BC.
  2. ABC=118\angle ABC = 118^\circ.
  3. DAB=42\angle DAB = 42^\circ.

Solution:

Step 1: Understanding the geometry of the problem

Since DEBCDE \parallel BC, ADE\triangle ADE and ABC\triangle ABC share properties related to parallel lines, particularly corresponding angles and linear angle relationships.

Step 2: Calculating EAD\angle EAD

From the given information: DAB=42\angle DAB = 42^\circ Thus: EAD=DAB=42\angle EAD = \angle DAB = 42^\circ (These are the same because DEBCDE \parallel BC and line ABAB serves as the transversal.)

Step 3: Using linear angles to find ADE\angle ADE

ADE\angle ADE and ABC\angle ABC are supplementary angles (on the same side of the transversal ABAB) because DEBCDE \parallel BC. Therefore: ADE+ABC=180\angle ADE + \angle ABC = 180^\circ Substitute ABC=118\angle ABC = 118^\circ: ADE+118=180\angle ADE + 118^\circ = 180^\circ ADE=180118=62\angle ADE = 180^\circ - 118^\circ = 62^\circ

Final Answer:

The value of ADE\angle ADE is 62°.

Would you like a breakdown of the reasoning or more related problems to practice? Let me know! Here are 5 related questions to explore further:

  1. If DEBCDE \parallel BC, how do corresponding angles relate to each other?
  2. What is the role of supplementary angles in parallel line problems?
  3. Can this problem be solved using alternate interior angles?
  4. If ABC\angle ABC changes, how does ADE\angle ADE change?
  5. How would the solution differ if the lines were not parallel?

Tip: Always verify which angles are supplementary or corresponding when dealing with parallel lines and a transversal.

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Math Problem Analysis

Mathematical Concepts

Geometry
Parallel Lines and Angles
Supplementary Angles

Formulas

Sum of supplementary angles: ∠1 + ∠2 = 180°

Theorems

Properties of parallel lines
Transversal and angle relationships

Suitable Grade Level

Grades 9-10