Math Problem Statement

Jawablah

Suku kedua dan suku kelima suatu barisan geometri berturut-turut adalah -6 dan 48. Suku keempat barisan geometri tersebut adalah...; Suku pertama dan rasio suatu barisan geometri berturut-turut adalah 2 dan 3. Jika jumlah n suku pertama deret tersebut adalah 80, tentukan banyak suku dari barisan tersebut.

Solution

The image contains two geometric sequence problems written in Indonesian. Let's break them down and solve them step by step.

Problem 1:

"Suku kedua dan suku kelima suatu barisan geometri berturut-turut adalah -6 dan 48. Suku keempat barisan geometri tersebut adalah…"

Translation:

  • The second term (suku kedua) and the fifth term (suku kelima) of a geometric sequence are -6 and 48, respectively. Find the fourth term of the sequence.

Solution:

In a geometric sequence, the nth term is given by: an=a1rn1a_n = a_1 \cdot r^{n-1} where:

  • ana_n is the nth term,
  • a1a_1 is the first term,
  • rr is the common ratio.

We are given:

  • a2=6a_2 = -6 (second term),
  • a5=48a_5 = 48 (fifth term).

Using the formula for each term:

  1. For the second term: a2=a1r=6a_2 = a_1 \cdot r = -6, a1r=6(1)a_1 \cdot r = -6 \quad (1)
  2. For the fifth term: a5=a1r4=48a_5 = a_1 \cdot r^4 = 48, a1r4=48(2)a_1 \cdot r^4 = 48 \quad (2)

Now, divide equation (2) by equation (1): a1r4a1r=486\frac{a_1 \cdot r^4}{a_1 \cdot r} = \frac{48}{-6} r3=8r^3 = -8 r=2r = -2

Substitute r=2r = -2 into equation (1): a1(2)=6a_1 \cdot (-2) = -6 a1=3a_1 = 3

Now, to find the fourth term (a4a_4): a4=a1r3=3(2)3=3(8)=24a_4 = a_1 \cdot r^3 = 3 \cdot (-2)^3 = 3 \cdot (-8) = -24

So, the fourth term is -24.


Problem 2:

"Suku pertama dan rasio suatu barisan geometri berturut-turut adalah 2 dan 3. Jika jumlah n suku pertama deret tersebut adalah 80, tentukan banyak suku dari barisan tersebut."

Translation:

  • The first term of a geometric sequence is 2, and the common ratio is 3. If the sum of the first n terms is 80, determine how many terms (n) are in the sequence.

Solution:

The sum of the first n terms in a geometric sequence is given by: Sn=a1rn1r1S_n = a_1 \cdot \frac{r^n - 1}{r - 1} where:

  • SnS_n is the sum of the first n terms,
  • a1=2a_1 = 2 is the first term,
  • r=3r = 3 is the common ratio.

We are given that Sn=80S_n = 80. Substituting the known values: 80=23n13180 = 2 \cdot \frac{3^n - 1}{3 - 1} 80=23n1280 = 2 \cdot \frac{3^n - 1}{2} 80=3n180 = 3^n - 1 81=3n81 = 3^n 3n=813^n = 81

Since 81=3481 = 3^4, we have: n=4n = 4

Thus, the number of terms (n) is 4.


Would you like more details on any of these solutions or have further questions?

Relative Questions:

  1. How do you find the first term of a geometric sequence if given other terms?
  2. What is the significance of the common ratio in a geometric sequence?
  3. Can geometric sequences have a common ratio that is a fraction?
  4. How can the sum formula for geometric sequences be applied to find missing terms?
  5. What happens if the common ratio in a geometric series is negative?

Tip:

In geometric sequences, knowing just two terms (that are far apart) can help you determine both the first term and the common ratio, allowing you to solve for any other terms.

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Math Problem Analysis

Mathematical Concepts

Geometric Sequences
Arithmetic in Sequences
Summation of Geometric Series

Formulas

General term of geometric sequence: a_n = a_1 * r^(n-1)
Sum of first n terms of geometric series: S_n = a_1 * (r^n - 1) / (r - 1)

Theorems

Formula for nth term of geometric sequence
Sum formula for geometric series

Suitable Grade Level

Grades 10-12