https://file.aiquickdraw.com/mathbot/file/1726964221825zo3gk0z7.jpg

Let's go through the questions based on the graph of "Regular Gasoline Prices in 2004":

### Question 11:
**What is the slope of the line from November to December?**

- To find the slope between November and December, we use the formula for slope:
  \[
  \text{slope} = \frac{{y_2 - y_1}}{{x_2 - x_1}}
  \]
  where \( y_2 \) and \( y_1 \) are the prices in December and November, respectively, and \( x_2 - x_1 \) is the time interval (1 month).

  From the graph:
  - Price in November (\( y_1 \)) = 1.40
  - Price in December (\( y_2 \)) = 1.38

  Substituting these values:
  \[
  \text{slope} = \frac{{1.38 - 1.40}}{{1}} = -0.02
  \]

  None of the provided options match exactly, but the closest would be **Option C** \(-0.04\).

### Question 12:
**During which time interval did the cost decrease at the greatest rate?**

- We look at the steepest slope, which corresponds to the greatest decrease in price.
- From the graph, the biggest drop is from **July to August** (from 1.52 to 1.48).

  Therefore, the correct answer is **F (Jul to Aug)**.

### Question 13:
**During which time interval was the slope positive?**

- A positive slope means an increase in the price of gasoline.
- From the graph, the only period with an increase is from **September to October** (from 1.42 to 1.44).

  So, the answer is **C (Sep to Oct)**.

### Question 14:
**What was the rate of change from October to December?**

- The rate of change from

What is the slope of the line from November to December? During which time interval did the cost decrease at the greatest rate? During which time interval was the slope positive? What was the rate of change from October to December?

Analyze the slope and rate of change in gasoline prices from July to December 2004. Solve questions related to slope from November to December, the greatest rate of decrease, and the positive slope interval. Suitable for Grades 7-9.

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