Math Problem Statement

Evaluate the following functions: f(x) = 2x - 11 at x = 10, f(x) = 6x^2 + 4x - 7 at x = 2, F(x) = 3x^2 + 5x + 1 at x = 2, f(k) = 5k + 1 at k = (k+2), f(x) = x - 2|2x - 7| at x = 7.

Solution

Let's go through the functions you provided in the image and evaluate them. Here is the breakdown of each one:

  1. f(x)=2x11,x=10f(x) = 2x - 11, \, x = 10 f(10)=2(10)11=2011=9f(10) = 2(10) - 11 = 20 - 11 = 9 Answer: f(10)=9f(10) = 9

  2. f(x)=6x2+4x7,x=2f(x) = 6x^2 + 4x - 7, \, x = 2 f(2)=6(22)+4(2)7=6(4)+87=24+87=25f(2) = 6(2^2) + 4(2) - 7 = 6(4) + 8 - 7 = 24 + 8 - 7 = 25 Answer: f(2)=25f(2) = 25

  3. F(x)=3x2+5x+1,x=2F(x) = 3x^2 + 5x + 1, \, x = 2 F(2)=3(22)+5(2)+1=3(4)+10+1=12+10+1=23F(2) = 3(2^2) + 5(2) + 1 = 3(4) + 10 + 1 = 12 + 10 + 1 = 23 Answer: F(2)=23F(2) = 23

  4. f(k)=5k+1,k=(k+2)f(k) = 5k + 1, \, k = (k+2) This one is a bit different, as it's a function where kk is substituted with k+2k+2: f(k)=5(k+2)+1=5k+10+1=5k+11f(k) = 5(k+2) + 1 = 5k + 10 + 1 = 5k + 11 Answer: f(k)=5k+11f(k) = 5k + 11

  5. f(x)=x22x7,x=7f(x) = x - 2|2x - 7|, \, x = 7 First, evaluate the absolute value: f(7)=722(7)7=72147=727=72(7)=714=7f(7) = 7 - 2|2(7) - 7| = 7 - 2|14 - 7| = 7 - 2|7| = 7 - 2(7) = 7 - 14 = -7 Answer: f(7)=7f(7) = -7

Would you like any further explanation or details?

Here are some follow-up questions you can explore:

  1. How do you handle functions that include absolute values in different cases (e.g., when the expression inside is negative)?
  2. What happens to the domain of a function if you introduce a square root or a fraction?
  3. How would you solve for unknown values inside a function (e.g., find kk in f(k)=5k+1f(k) = 5k + 1)?
  4. Can you describe how polynomials like 3x2+5x+13x^2 + 5x + 1 behave as xx grows larger?
  5. What are some real-life applications where absolute values in functions matter?

Tip: Always start by simplifying the inner expressions (like absolute values or powers) before substituting specific values.

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Math Problem Analysis

Mathematical Concepts

Algebra
Function Evaluation
Absolute Value

Formulas

f(x) = 2x - 11
f(x) = 6x^2 + 4x - 7
F(x) = 3x^2 + 5x + 1
f(k) = 5k + 1
f(x) = x - 2|2x - 7|

Theorems

Basic Algebraic Manipulation
Absolute Value Theorem

Suitable Grade Level

Grades 9-12