Math Problem Statement

f(0)=2*(0)^2+7*0+5

Solution

To evaluate the function f(x)=2x2+7x+5f(x) = 2x^2 + 7x + 5 at x=0x = 0, substitute x=0x = 0 into the function:

f(0)=2(0)2+7(0)+5f(0) = 2(0)^2 + 7(0) + 5

Simplifying the expression:

f(0)=2(0)+0+5=5f(0) = 2(0) + 0 + 5 = 5

So, f(0)=5f(0) = 5.

Would you like more details or have any questions?

Here are some related questions you might consider:

  1. What is f(1)f(1) for the same function?
  2. How does the function f(x)f(x) behave as xx increases?
  3. What are the roots of the function f(x)=0f(x) = 0?
  4. How would the graph of f(x)f(x) look like?
  5. What is the vertex of the parabola represented by f(x)f(x)?

Tip: When evaluating a function at a specific point, always substitute the value directly into the function and simplify carefully.

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Math Problem Analysis

Mathematical Concepts

Quadratic Equations
Function Evaluation

Formulas

Quadratic equation formula: ax^2 + bx + c

Theorems

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Suitable Grade Level

Grades 7-9