Math Problem Statement

  1. Given 𝑓(𝑥) = −2𝑥 2 − 3𝑥 + 8 𝑔(𝑥) = 2𝑥 − 5 Find the indicated composition. Show all work. a. (𝑓 ∘ 𝑔)(𝑥) b. (𝑔 ∘ 𝑓)(4)

Solution

We are tasked with finding two compositions of functions, one for (fg)(x)(f \circ g)(x) and another for (gf)(4)(g \circ f)(4). Let's break this down step by step:

Given functions:

  • f(x)=2x23x+8f(x) = -2x^2 - 3x + 8
  • g(x)=2x5g(x) = 2x - 5

Part (a): (fg)(x)(f \circ g)(x)

This represents f(g(x))f(g(x)), meaning we will substitute g(x)g(x) into the function f(x)f(x).

Step 1: Substitute g(x)=2x5g(x) = 2x - 5 into f(x)f(x).

The function f(x)=2x23x+8f(x) = -2x^2 - 3x + 8 becomes: f(g(x))=f(2x5)f(g(x)) = f(2x - 5)

Step 2: Replace xx in f(x)f(x) with 2x52x - 5:

f(2x5)=2(2x5)23(2x5)+8f(2x - 5) = -2(2x - 5)^2 - 3(2x - 5) + 8

Step 3: Simplify each term:

  • First, simplify (2x5)2(2x - 5)^2: (2x5)2=(2x)22(2x)(5)+(5)2=4x220x+25(2x - 5)^2 = (2x)^2 - 2(2x)(5) + (5)^2 = 4x^2 - 20x + 25
  • Now substitute this result back into the equation: f(2x5)=2(4x220x+25)3(2x5)+8f(2x - 5) = -2(4x^2 - 20x + 25) - 3(2x - 5) + 8

Step 4: Distribute:

f(2x5)=2(4x2)+2(20x)2(25)3(2x)+3(5)+8f(2x - 5) = -2(4x^2) + 2(20x) - 2(25) - 3(2x) + 3(5) + 8 =8x2+40x506x+15+8= -8x^2 + 40x - 50 - 6x + 15 + 8

Step 5: Combine like terms:

f(2x5)=8x2+34x27f(2x - 5) = -8x^2 + 34x - 27

Thus, the composition (fg)(x)=8x2+34x27(f \circ g)(x) = -8x^2 + 34x - 27.

Part (b): (gf)(4)(g \circ f)(4)

This represents g(f(4))g(f(4)), meaning we first evaluate f(4)f(4), then substitute that result into g(x)g(x).

Step 1: Find f(4)f(4).

Substitute x=4x = 4 into f(x)f(x): f(4)=2(4)23(4)+8f(4) = -2(4)^2 - 3(4) + 8 =2(16)12+8=3212+8=36= -2(16) - 12 + 8 = -32 - 12 + 8 = -36

Step 2: Find g(f(4))=g(36)g(f(4)) = g(-36).

Now substitute 36-36 into g(x)g(x): g(36)=2(36)5=725=77g(-36) = 2(-36) - 5 = -72 - 5 = -77

Thus, (gf)(4)=77(g \circ f)(4) = -77.

Final Answers:

  • (fg)(x)=8x2+34x27(f \circ g)(x) = -8x^2 + 34x - 27
  • (gf)(4)=77(g \circ f)(4) = -77

Would you like further details or explanations?


Here are five related questions to expand on this topic:

  1. How do you find the domain of the composition of two functions?
  2. What is the difference between f(g(x))f(g(x)) and g(f(x))g(f(x))?
  3. Can compositions of functions be commutative (i.e., f(g(x))=g(f(x))f(g(x)) = g(f(x)))?
  4. How does function composition relate to real-world applications, such as in physics or economics?
  5. What happens to the graph of a function when it's composed with another function?

Tip: Always simplify inner functions first when working with compositions to avoid errors!

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Math Problem Analysis

Mathematical Concepts

Function Composition
Quadratic Functions
Linear Functions

Formulas

Function composition: (f ∘ g)(x) = f(g(x))
Quadratic expansion: (a + b)^2 = a^2 + 2ab + b^2

Theorems

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Suitable Grade Level

Grades 10-12