Math Problem Statement

f(x)=7-4x and g(x)=2+x^2 (f ∘ g)(x)=

Solution

To find (fg)(x)(f \circ g)(x), also known as the composition of functions ff and gg, you substitute g(x)g(x) into f(x)f(x). In other words:

(fg)(x)=f(g(x))(f \circ g)(x) = f(g(x))

Given that:

  • f(x)=74xf(x) = 7 - 4x
  • g(x)=2+x2g(x) = 2 + x^2

Now, substitute g(x)g(x) into f(x)f(x):

(fg)(x)=f(g(x))=f(2+x2)(f \circ g)(x) = f(g(x)) = f(2 + x^2)

Substitute 2+x22 + x^2 into f(x)f(x):

f(2+x2)=74(2+x2)f(2 + x^2) = 7 - 4(2 + x^2)

Simplify the expression:

f(2+x2)=74(2)4(x2)f(2 + x^2) = 7 - 4(2) - 4(x^2) =784x2= 7 - 8 - 4x^2 =14x2= -1 - 4x^2

Thus, the composition of ff and gg is:

(fg)(x)=14x2(f \circ g)(x) = -1 - 4x^2

Would you like further details on function composition or any other clarification?

Here are 5 related questions to consider:

  1. How would you compute (gf)(x)(g \circ f)(x)?
  2. What happens if f(x)f(x) and g(x)g(x) are inverse functions?
  3. Can you find the domain of (fg)(x)(f \circ g)(x)?
  4. How does function composition affect the range of the resulting function?
  5. Can you graph f(x)f(x), g(x)g(x), and (fg)(x)(f \circ g)(x) to visualize the result?

Tip: In function composition, pay careful attention to the order of the functions. f(g(x))f(g(x)) is not the same as g(f(x))g(f(x)).

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Math Problem Analysis

Mathematical Concepts

Function Composition
Quadratic Functions
Algebra

Formulas

(f ∘ g)(x) = f(g(x))
f(x) = 7 - 4x
g(x) = 2 + x^2

Theorems

Function Composition Theorem

Suitable Grade Level

Grades 9-12