Last month, Maya and Jeffrey sold candy to raise money for their debate team. Jeff sold 3/8 as much candy as May did if May sold 1/2 of a box of candy. How many boxes of candy did Jeffrey sell?

To find how many boxes of candy Jeffrey sold, we can follow these steps:

1. We know that May sold \( \frac{1}{2} \) of a box of candy.
2. Jeffrey sold \( \frac{3}{8} \) as much as May.

To calculate the amount Jeffrey sold, multiply the amount May sold by \( \frac{3}{8} \):

\[
\text{Jeffrey's amount} = \frac{3}{8} \times \frac{1}{2}
\]

Now, multiply the fractions:

\[
\text{Jeffrey's amount} = \frac{3 \times 1}{8 \times 2} = \frac{3}{16}
\]

So, Jeffrey sold \( \frac{3}{16} \) of a box of candy.

### Final Answer: 
Jeffrey sold \( \frac{3}{16} \) of a box of candy.

Would you like more details on fraction multiplication or any other clarifications?

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Here are some related questions to explore:
1. If May sold a full box of candy, how much would Jeffrey have sold?
2. How much more candy did May sell compared to Jeffrey?
3. If Jeffrey sold twice as much as he originally did, how many boxes would that be?
4. What fraction of a box did both May and Jeffrey sell together?
5. If another person sold \( \frac{5}{8} \) of a box, how would that compare to Jeffrey's sales?

**Tip:** When multiplying fractions, always multiply the numerators and the denominators separately!

Discover how to calculate how many boxes of candy Jeffrey sold, given that he sold 3/8 as much as May, who sold 1/2 of a box. This problem involves multiplying fractions and is suitable for students in Grades 5-6.

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