Math Problem Statement

what is the resultant

Calculate the summation of all forces (both for x and y components). Assume F1 to be perpendicular to F2 and parallel to F3.

Solution

To find the resultant force from the given diagram, we need to calculate the sum of all forces in both the xx- and yy-directions. Let’s break down the forces step by step.

Given Information:

  • F1=30lbfF_1 = 30 \, \text{lbf} at an angle of 6060^\circ from the negative xx-axis
  • F2=18lbfF_2 = 18 \, \text{lbf} along the positive xx-axis
  • F3=5lbfF_3 = 5 \, \text{lbf} along the negative yy-axis
  • F4=10lbfF_4 = 10 \, \text{lbf} along the negative yy-axis

Breaking down the forces into components:

Force F1F_1:

  • F1F_1 makes a 6060^\circ angle with the negative xx-axis.
  • F1x=F1cos(60)=30cos(60)F_{1x} = -F_1 \cos(60^\circ) = -30 \cos(60^\circ)
  • F1y=F1sin(60)=30sin(60)F_{1y} = F_1 \sin(60^\circ) = 30 \sin(60^\circ)

Force F2F_2:

  • F2F_2 is along the positive xx-axis.
  • F2x=18lbfF_{2x} = 18 \, \text{lbf}
  • F2y=0F_{2y} = 0

Force F3F_3:

  • F3F_3 is along the negative yy-axis.
  • F3x=0F_{3x} = 0
  • F3y=5lbfF_{3y} = -5 \, \text{lbf}

Force F4F_4:

  • F4F_4 is along the negative yy-axis.
  • F4x=0F_{4x} = 0
  • F4y=10lbfF_{4y} = -10 \, \text{lbf}

Summing up the components:

Sum of xx-components:

ΣFx=F1x+F2x+F3x+F4x\Sigma F_x = F_{1x} + F_{2x} + F_{3x} + F_{4x}

Sum of yy-components:

ΣFy=F1y+F2y+F3y+F4y\Sigma F_y = F_{1y} + F_{2y} + F_{3y} + F_{4y}

Now, let's calculate these values and find the magnitude of the resultant force FRF_R and its direction.### Results:

  1. Sum of xx-components: ΣFx=3.0000lbf\Sigma F_x = 3.0000 \, \text{lbf}
  2. Sum of yy-components: ΣFy=10.9808lbf\Sigma F_y = 10.9808 \, \text{lbf}
  3. Resultant force: FR=11.3832lbfF_R = 11.3832 \, \text{lbf}
  4. Direction of the resultant: θR=74.7194\theta_R = 74.7194^\circ (from the positive xx-axis)

The resultant force has a magnitude of 11.3832 lbf and is directed at an angle of 74.72° from the positive xx-axis.

Would you like more details or have any questions?


Here are 5 related questions:

  1. How would the resultant force change if F2F_2 increased?
  2. What would happen to the resultant direction if F1F_1 were doubled?
  3. How can we decompose forces into components for other angles?
  4. How does the system behave if F3F_3 acts at a different angle?
  5. What is the effect of force direction changes on the resultant magnitude?

Tip: Always check that the angle reference for forces aligns with the coordinate axes when resolving components.

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Math Problem Analysis

Mathematical Concepts

Vector Components
Force Summation
Trigonometry

Formulas

Sum of forces in x-direction: ΣFx = F1x + F2x + F3x + F4x
Sum of forces in y-direction: ΣFy = F1y + F2y + F3y + F4y
Resultant force: FR = sqrt((ΣFx)^2 + (ΣFy)^2)
Angle of resultant: θ = atan(ΣFy / ΣFx)

Theorems

Pythagorean theorem for calculating resultant force
Trigonometric identity for angle determination

Suitable Grade Level

College-level Physics