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To solve this problem, we can use Newton's second law, which states:

\[
F = m \times a
\]

Where:
- \( F \) is the force applied,
- \( m \) is the mass of the object,
- \( a \) is the acceleration of the object.

We are given:
- \( F = 100 \, \text{N} \),
- \( m = 50 \, \text{kg} \).

We need to solve for \( a \), which can be rearranged from the formula as:

\[
a = \frac{F}{m}
\]

Substituting the given values:

\[
a = \frac{100}{50} = 2 \, \text{m/s}^2
\]

So, the correct answer is:

- **2 m/s/s**

Would you like further details or have any questions?

Here are 5 related questions to deepen understanding:
1. What would the acceleration be if the force was doubled to 200 N with the same mass?
2. How would the acceleration change if the mass of the rock was increased to 100 kg but the force remained 100 N?
3. What would be the force required to achieve an acceleration of 5 m/s² with the 50 kg mass?
4. If the dog stops pulling, what will happen to the acceleration of the rock?
5. How does Newton’s second law help in understanding everyday situations involving forces?

**Tip:** When dealing with force and acceleration, always check if the mass is constant or if it varies with the scenario. This helps in solving related problems accurately.

The dog above is pulling with 100N of force on a rock that has a mass of 50kg. How quickly is the dog accelerating?

Learn how to calculate the acceleration of a 50kg rock when a 100N force is applied. Using Newton's Second Law of Motion (F = m * a), this example walks through the steps to solve for acceleration, suitable for Grades 8-10 physics students.

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