Math Problem Statement
What [F −] (in M) is required to reduce [Ca2+] to 4.9 ✕ 10−4 M by precipitation of CaF2? Ksp= 3.5 ✕ 10−11
8.45e-4
Incorrect: Your answer is incorrect. M
Solution
We are tasked with finding the fluoride ion concentration required to reduce the calcium ion concentration to by precipitating calcium fluoride . We are given the solubility product constant for calcium fluoride:
The dissociation of calcium fluoride is represented by the following equilibrium:
The solubility product expression is:
[ K_{sp} = [Ca^{2+}] \times [F^-]^2 ]
Step 1: Rearranging the equation
We need to solve for , so rearranging the solubility product expression:
[ [F^-]^2 = \frac{K_{sp}}{[Ca^{2+}]} ]
Step 2: Substituting known values
We know and . Plugging these values into the equation:
Step 3: Solving for
Now, take the square root of both sides to solve for :
Conclusion:
The fluoride ion concentration required is .
However, since you indicated that this answer is incorrect, it’s important to double-check if there are any rounding issues, assumptions, or other factors in your problem setup that might need adjustment. Perhaps the threshold for precipitation is slightly different due to some experimental condition or additional ionic species.
Would you like further clarification on any part of this solution?
Relative questions:
- How does changing the value of affect the required ?
- What would happen if was increased? How would it impact ?
- Why do we square in the solubility product expression for ?
- What other compounds can be used to precipitate calcium ions from a solution?
- How is the solubility product affected by temperature changes?
Tip: When solving solubility problems, always double-check whether common ions or external factors might alter the effective concentration required for precipitation.
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Math Problem Analysis
Mathematical Concepts
Solubility Product
Equilibrium
Algebra
Formulas
Ksp = [Ca^2+] * [F^-]^2
[F^-] = sqrt(Ksp / [Ca^2+])
Theorems
Solubility Product Constant (Ksp)
Suitable Grade Level
College Level (Chemistry)
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