Math Problem Statement

The probability of flu symptoms for a person not receiving any treatment is 0.046. In a clinical trial of a common drug used to lower​ cholesterol, 57 of 1178 people treated experienced flu symptoms. Assuming the drug has no effect on the likelihood of flu​ symptoms, estimate the probability that at least 57 people experience flu symptoms. What do these results suggest about flu symptoms as an adverse reaction to the​ drug?

Solution

We are tasked with estimating the probability that at least 57 people in a sample of 1178 experience flu symptoms, given the probability of flu symptoms in the general population (without treatment) is 0.046. To solve this, we can model the problem using a binomial distribution and apply a normal approximation due to the large sample size.

Step 1: Define the Binomial Model

The number of people experiencing flu symptoms follows a binomial distribution, where:

  • n=1178n = 1178 is the number of people in the trial.
  • p=0.046p = 0.046 is the probability of a person experiencing flu symptoms.

The number of people experiencing flu symptoms, XX, is binomially distributed:
XBinomial(n=1178,p=0.046)X \sim \text{Binomial}(n=1178, p=0.046)

Step 2: Compute the Mean and Standard Deviation

For a binomial distribution, the mean μ\mu and the standard deviation σ\sigma are calculated as follows:

  • μ=np=1178×0.046=54.188\mu = np = 1178 \times 0.046 = 54.188
  • σ=np(1p)=1178×0.046×(10.046)7.288\sigma = \sqrt{np(1-p)} = \sqrt{1178 \times 0.046 \times (1 - 0.046)} \approx 7.288

Step 3: Use Normal Approximation

Since nn is large, we can approximate the binomial distribution with a normal distribution N(μ,σ)N(\mu, \sigma), where:

  • μ=54.188\mu = 54.188
  • σ7.288\sigma \approx 7.288

We are interested in finding the probability that at least 57 people experience flu symptoms, i.e., P(X57)P(X \geq 57).

To use the normal approximation, apply a continuity correction by finding P(X56.5)P(X \geq 56.5).

Step 4: Compute the Z-Score

The z-score is calculated as follows: Z=56.5μσ=56.554.1887.2880.317Z = \frac{56.5 - \mu}{\sigma} = \frac{56.5 - 54.188}{7.288} \approx 0.317

Step 5: Find the Probability

Using standard normal distribution tables or a calculator, find the probability corresponding to Z=0.317Z = 0.317.

  • P(Z0.317)0.376P(Z \geq 0.317) \approx 0.376

Interpretation of Results

The probability that at least 57 people experience flu symptoms, given that the drug has no effect, is about 0.376 or 37.6%. This is a relatively high probability, suggesting that the observed result (57 people experiencing flu symptoms) is not unusual and could occur by chance if the drug had no effect on the likelihood of flu symptoms.

Conclusion:

Since the probability is reasonably high, this suggests that flu symptoms observed in the clinical trial are not likely caused by the drug as an adverse reaction. The results are consistent with the assumption that the drug does not increase the likelihood of flu symptoms.


Would you like more details or have any questions about this?

Here are 5 related questions you might explore:

  1. How would the result change if a larger number of participants experienced flu symptoms?
  2. What if the base probability of flu symptoms was higher, say 0.1? How would that affect the outcome?
  3. How does the continuity correction improve the normal approximation?
  4. Can the central limit theorem be applied directly in this problem, and why?
  5. How would the analysis change if the sample size was smaller?

Tip: Always check the assumptions (such as sample size and probability) before applying normal approximation to binomial distributions.

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Math Problem Analysis

Mathematical Concepts

Probability
Binomial Distribution
Normal Approximation
Z-Score

Formulas

Mean: μ = np
Standard Deviation: σ = sqrt(np(1-p))
Z-Score: Z = (X - μ) / σ
P(X ≥ k): P(Z ≥ z)

Theorems

Central Limit Theorem
Normal Approximation to Binomial Distribution

Suitable Grade Level

College/University Level - Statistics