To find the best point estimate of the population proportion $p$, we use the formula:

$\hat{p} = \frac{x}{n}$

where:

• $x$ is the number of patients who developed the adverse reaction (nausea),
• $n$ is the total number of patients treated.

From the problem:

• $x = 185$,
• $n = 4405$.

Now calculate $\hat{p}$:

$\hat{p} = \frac{185}{4405} \approx 0.042$

Thus, the best point estimate of the population proportion $p$ is:

$\hat{p} = 0.042$

Would you like further details or explanations on this?

Here are 5 follow-up questions:

1. How would you calculate the margin of error for a confidence interval?
2. What formula is used to construct a confidence interval for a population proportion?
3. How does increasing the confidence level affect the width of the confidence interval?
4. Why is the point estimate of a population proportion important in statistics?
5. What assumptions must be met for the confidence interval calculation to be valid?

Tip: Always check if the sample size is large enough to assume a normal distribution for proportions when constructing confidence intervals.