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The problem asks us to find the first three terms of a sequence where the \(n^{\text{th}}\) term is given by the formula:

\[
T_n = 20 - 3n
\]

To calculate the first three terms, we substitute \(n = 1\), \(n = 2\), and \(n = 3\) into the formula.

1. For \(n = 1\):
\[
T_1 = 20 - 3(1) = 20 - 3 = 17
\]

2. For \(n = 2\):
\[
T_2 = 20 - 3(2) = 20 - 6 = 14
\]

3. For \(n = 3\):
\[
T_3 = 20 - 3(3) = 20 - 9 = 11
\]

Therefore, the first three terms of the sequence are: **17, 14, 11**.

Would you like further details or have any other questions?

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Here are some follow-up questions to deepen your understanding:
1. What is the fourth term in the sequence?
2. Can you find the general formula for the \(n^{\text{th}}\) term of any arithmetic sequence?
3. How do we determine the common difference in this sequence?
4. What type of sequence is this (arithmetic or geometric)?
5. Can you determine the 10th term using the same formula?

**Tip:** In an arithmetic sequence, the difference between consecutive terms is always constant, called the "common difference".

The nth term of a sequence is given by 20 - 3n. Work out the first three terms in the sequence.

Learn how to calculate the first three terms of a sequence using the formula T_n = 20 - 3n. This problem involves basic algebra and arithmetic sequences, making it ideal for students in Grades 7-9.

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