To find the vertex of the quadratic function $f(x) = -3(x - 2)^2 - 4$, we can use the vertex form of a quadratic equation, which is:

$f(x) = a(x - h)^2 + k$

Here:

• $a = -3$ (the coefficient of the squared term),
• $h = 2$ (the value inside the parentheses),
• $k = -4$ (the constant outside the squared term).

The vertex of a quadratic function in vertex form is given by the point $(h, k)$. Therefore, the vertex of this quadratic is:

$(2, -4)$

Would you like more details or have any questions?

Here are 5 related questions to explore further:

1. What is the axis of symmetry of this quadratic function?
2. How does the value of $a$ affect the direction of the parabola?
3. How do you convert a quadratic function from vertex form to standard form?
4. What is the effect of shifting the vertex on the graph of a quadratic?
5. How do you determine the minimum or maximum value of a quadratic function?

Tip: When the coefficient $a$ is negative, the parabola opens downward, and the vertex represents the maximum point of the function.