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To find the vertex of the quadratic function \( f(x) = -3(x - 2)^2 - 4 \), we can use the vertex form of a quadratic equation, which is:

\[
f(x) = a(x - h)^2 + k
\]

Here:
- \( a = -3 \) (the coefficient of the squared term),
- \( h = 2 \) (the value inside the parentheses),
- \( k = -4 \) (the constant outside the squared term).

The vertex of a quadratic function in vertex form is given by the point \( (h, k) \). Therefore, the vertex of this quadratic is:

\[
(2, -4)
\]

Would you like more details or have any questions? 

Here are 5 related questions to explore further:
1. What is the axis of symmetry of this quadratic function?
2. How does the value of \( a \) affect the direction of the parabola?
3. How do you convert a quadratic function from vertex form to standard form?
4. What is the effect of shifting the vertex on the graph of a quadratic?
5. How do you determine the minimum or maximum value of a quadratic function?

**Tip:** When the coefficient \( a \) is negative, the parabola opens downward, and the vertex represents the maximum point of the function.

Find the vertex of the quadratic function: f(x) = -3(x - 2)^2 - 4.

Learn how to find the vertex of the quadratic function f(x) = -3(x - 2)^2 - 4. This problem explores key concepts of vertex form and quadratic functions, suitable for students in Grades 8-10.

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