The function given is:

$f(x) = (x - 3)^2 - 4$

This is a quadratic function written in vertex form, $f(x) = a(x-h)^2 + k$, where $(h, k)$ is the vertex of the parabola.

Here, we can directly see that:

• $h = 3$ (because of $(x - 3)$ in the expression)
• $k = -4$ (the constant term at the end)

Thus, the vertex of the function is $(3, -4)$.

Would you like further details or have any questions about this?

Here are 5 related questions:

1. How does the vertex form of a quadratic function differ from standard form?
2. Can you determine whether this parabola opens upwards or downwards?
3. What role does the value of $a$ play in the shape of the parabola?
4. How can we find the axis of symmetry for this function?
5. Can you find the x-intercepts of the function by solving $f(x) = 0$?

Tip: The vertex form of a quadratic equation makes it easy to identify the vertex and direction of the parabola, making it especially useful for graphing.