The vertex form of a quadratic function is generally written as:

$y = a(x - h)^2 + k$

where $(h, k)$ is the vertex of the parabola.

Given the function:

$y = 2(x - 3)^2 + 4$

• $h = 3$
• $k = 4$

Thus, the vertex is:

$(3, 4)$

So, the correct answer is (3, 4).

Would you like to see further details or have any questions?

Here are 5 related questions:

1. What is the axis of symmetry for the function $y = 2(x - 3)^2 + 4$?
2. How do you find the x-intercepts of a quadratic function?
3. What is the effect of changing the value of $a$ in the vertex form of a quadratic function?
4. How would the graph of the function change if the equation was $y = 2(x + 3)^2 + 4$?
5. How do you find the y-intercept of a quadratic function in vertex form?

Tip: The sign of $h$ in the vertex form $y = a(x - h)^2 + k$ is always opposite when determining the vertex.