Math Problem Statement

Find the length of EG using the provided segment lengths.

Solution

The problem provided is to find the length of EGEG on a line segment involving several sub-segments. Here's what we have from the image:

  • EE to FF has a length of x+23x + 23,
  • FF to GG has a length of 14+x14 + x,
  • GG to HH has a length of 12,
  • The total length from EE to HH is 26.

We want to find EGEG, which is the length from EE to GG.

Step 1: Express the total length of EHEH

The total length EHEH is: EH=EF+FG+GHEH = EF + FG + GH Substituting the given values: 26=(x+23)+(14+x)+1226 = (x + 23) + (14 + x) + 12

Step 2: Simplify and solve for xx

Simplify the equation: 26=(x+23)+(14+x)+1226 = (x + 23) + (14 + x) + 12 26=2x+23+14+1226 = 2x + 23 + 14 + 12 26=2x+4926 = 2x + 49 Now solve for xx: 2649=2x26 - 49 = 2x 23=2x-23 = 2x x=232=11.5x = -\frac{23}{2} = -11.5

Step 3: Find EGEG

Now, we can find EGEG. The length EGEG is the sum of EFEF and FGFG, so: EG=(x+23)+(14+x)EG = (x + 23) + (14 + x) Substitute x=11.5x = -11.5: EG=(11.5+23)+(1411.5)EG = (-11.5 + 23) + (14 - 11.5) EG=11.5+2.5=14EG = 11.5 + 2.5 = 14

Thus, the length of EGEG is 1414.


Let me know if you need further details or have any questions!

Related Questions:

  1. How would the problem change if the total length of EHEH was 30 instead of 26?
  2. What would be the value of xx if the segment GHGH had a different length?
  3. How can we use algebraic expressions to represent line segments in geometry problems?
  4. Why is it necessary to solve for xx before calculating the length of EGEG?
  5. How can this type of problem help in understanding coordinate geometry?

Tip:

Always organize your information clearly when solving geometry problems involving multiple line segments!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Geometry
Linear Equations

Formulas

Total length of segment: EH = EF + FG + GH
Simplification and solving for x in a linear equation

Theorems

-

Suitable Grade Level

Grade 7-8