Math Problem Statement

1. Find the inverse of f(x) = x^5. 2. Find the inverse of f(x) = 9th root of (x + 3). 3. Find the inverse of f(x) = (x + 1)^7 - 3.

Solution

Let's solve the problems one by one.

1. Find the inverse of f(x)=x5f(x) = x^5

To find the inverse of this function:

  • Start by writing y=x5y = x^5.
  • Solve for xx in terms of yy: y=x5    x=y5y = x^5 \implies x = \sqrt[5]{y}
  • Now, switch yy and xx to express the inverse: f1(x)=x5f^{-1}(x) = \sqrt[5]{x} So, the inverse is f1(x)=x5f^{-1}(x) = \sqrt[5]{x}.

2. Find the inverse of f(x)=x+39f(x) = \sqrt[9]{x + 3}

For this one:

  • Write y=x+39y = \sqrt[9]{x + 3}.
  • Eliminate the radical by raising both sides to the power of 9: y9=x+3y^9 = x + 3
  • Solve for xx: x=y93x = y^9 - 3
  • Finally, switch yy and xx: f1(x)=x93f^{-1}(x) = x^9 - 3 So, the inverse is f1(x)=x93f^{-1}(x) = x^9 - 3, which matches the provided answer.

3. Find the inverse of f(x)=(x+1)73f(x) = (x + 1)^7 - 3

For this function:

  • Write y=(x+1)73y = (x + 1)^7 - 3.
  • Solve for xx. First, add 3 to both sides: y+3=(x+1)7y + 3 = (x + 1)^7
  • Take the 7th root of both sides: y+37=x+1\sqrt[7]{y + 3} = x + 1
  • Subtract 1 from both sides: x=y+371x = \sqrt[7]{y + 3} - 1
  • Switch yy and xx: f1(x)=x+371f^{-1}(x) = \sqrt[7]{x + 3} - 1 So, the inverse is f1(x)=x+371f^{-1}(x) = \sqrt[7]{x + 3} - 1.

Do you need further clarification or more details?

Here are 5 related questions:

  1. How do you verify if two functions are inverses of each other?
  2. What are the conditions for a function to have an inverse?
  3. How would you find the inverse of a logarithmic function?
  4. Can all polynomial functions be inverted? Why or why not?
  5. How does the graph of a function compare to the graph of its inverse?

Tip: Remember, when solving for the inverse of a function, the goal is to express the dependent variable in terms of the independent variable, then swap them!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Inverse functions
Radicals
Polynomials

Formulas

f(x) = x^5 → f^-1(x) = x^(1/5)
f(x) = 9th root of (x + 3) → f^-1(x) = (x^9 - 3)
f(x) = (x + 1)^7 - 3 → f^-1(x) = (x + 3)^(1/7) - 1

Theorems

Inverse function theorem

Suitable Grade Level

Grades 10-12