Math Problem Statement

For the function \( f(x) = \sqrt[5]{x} - 2 \), find \( f^{-1}(x) \).

Solution

We are given the function f(x)=x52f(x) = \sqrt[5]{x} - 2, and we are asked to find the inverse function f1(x)f^{-1}(x).

To find the inverse function, we follow these steps:

  1. Start by setting y=f(x)y = f(x), so y=x52y = \sqrt[5]{x} - 2.

  2. Now, solve for xx in terms of yy by isolating xx.

    First, add 2 to both sides of the equation: y+2=x5y + 2 = \sqrt[5]{x}

  3. Now, raise both sides of the equation to the power of 5 to remove the fifth root: (y+2)5=x(y + 2)^5 = x

  4. The inverse function is obtained by switching xx and yy: f1(x)=(x+2)5f^{-1}(x) = (x + 2)^5

Thus, the correct inverse function is f1(x)=(x+2)5f^{-1}(x) = (x + 2)^5.

From the answer choices, the correct option is: f1(x)=(x+2)5f^{-1}(x) = (x + 2)^5


Do you need further details or have any questions?

Here are 5 related questions to expand on this concept:

  1. How do you verify that two functions are inverses of each other?
  2. What is the domain and range of the inverse function f1(x)f^{-1}(x)?
  3. How does the behavior of the function f(x)=x52f(x) = \sqrt[5]{x} - 2 change when you add or subtract constants?
  4. What are the general steps to find the inverse of any function?
  5. Can every function have an inverse? Why or why not?

Tip: When finding an inverse, make sure to express the original variable completely in terms of the new one and then swap them to get the final form.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Inverse Functions

Formulas

Inverse Function Formula: Solve for x in terms of y and swap variables

Theorems

Inverse Function Theorem

Suitable Grade Level

Grades 10-12