The graph you've provided appears to be of a reciprocal function with vertical asymptotes, which suggests that it might be of the form:

$f(x) = \frac{a}{(x - h)} + k$

This form represents a transformed reciprocal function where:

• $a$ controls the steepness or vertical stretch/compression.
• $h$ shifts the graph horizontally (the asymptotes occur at $x = h$).
• $k$ shifts the graph vertically.

Steps to find the equation from the graph:

1. Identify vertical asymptotes: The vertical asymptotes occur where the function is undefined (division by zero). Based on the graph, there are vertical asymptotes at $x = -4$ and $x = 4$, which suggests the equation might involve factors like $(x - 4)$ and $(x + 4)$.

2. Identify horizontal asymptote: The horizontal asymptote appears to be $y = 0$, meaning the function approaches $0$ as $x \to \infty$ or $x \to -\infty$. This suggests no vertical shift ($k = 0$).

3. Formulate the equation: Given that there are two asymptotes, the form could be: $f(x) = \frac{a}{(x - 4)(x + 4)}$ This incorporates the asymptotes at $x = 4$ and $x = -4$.

4. Determine the value of $a$: To find the value of $a$, we need a point from the graph where the function passes through, other than at the asymptotes or the horizontal asymptote. For example, if the graph passes through $(0, 1)$, substitute this into the equation: $1 = \frac{a}{(0 - 4)(0 + 4)} = \frac{a}{-16}$ Solving for $a$: $a = -16$ So, the equation of the function would be: $f(x) = \frac{-16}{(x - 4)(x + 4)}$ Alternatively, you can identify another point on the graph to confirm or adjust $a$.

Final equation:

$f(x) = \frac{-16}{x^2 - 16}$ This represents a reciprocal function with vertical asymptotes at $x = 4$ and $x = -4$, a horizontal asymptote at $y = 0$, and steepness controlled by $a = -16$.

Would you like further details on any specific steps, or do you want to verify the equation with additional points?

5 Related Questions:

1. How do horizontal and vertical asymptotes affect the behavior of reciprocal functions?
2. What is the impact of varying $a$ on the steepness and direction of the graph?
3. Can we transform this graph by shifting the horizontal asymptote? How would that affect the equation?
4. What are other types of reciprocal functions, and how do their graphs differ?
5. How do you determine the domain and range of a reciprocal function from its graph?

Tip:

When analyzing a reciprocal function's graph, always begin by identifying the vertical and horizontal asymptotes, as these guide the general form of the function.