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To find \( \cot A \) in a right triangle, we can use the formula:

\[
\cot A = \frac{\text{adjacent side}}{\text{opposite side}}
\]

In this triangle:
- The side adjacent to angle \( A \) is 15.
- The side opposite angle \( A \) is 8.

Thus,

\[
\cot A = \frac{15}{8}
\]

So, the value of \( \cot A \) is \( \frac{15}{8} \) or 1.875 in decimal form.

Would you like more details or have any questions?

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Here are some related questions for further exploration:

1. How do we find other trigonometric ratios for angle \( A \) in this triangle?
2. What would \( \cot A \) be if we only knew the hypotenuse and one side?
3. How can we find angle \( A \) using trigonometric functions?
4. How is \( \cot A \) related to \( \tan A \) in terms of their values?
5. Can we calculate \( \cot A \) using other trigonometric identities?

**Tip:** Remember that \( \cot \theta = \frac{1}{\tan \theta} \), so once you know \( \tan \theta \), you can quickly find \( \cot \theta \).

Learn how to find the cotangent (cotA) in a right triangle with side lengths of 15 (adjacent) and 8 (opposite). This trigonometry problem provides step-by-step guidance, ideal for students in Grades 9-10.

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