To find the y-intercept of the function \( y = 2(x - 1)(x + 2) \), we need to determine the value of \( y \) when \( x = 0 \).

1. Substitute \( x = 0 \) into the equation:
   \[
   y = 2(0 - 1)(0 + 2)
   \]

2. Simplify the expression:
   \[
   y = 2(-1)(2)
   \]
   \[
   y = 2 \times -2 = -4
   \]

Therefore, the y-intercept is \( -4 \), or the point \( (0, -4) \).

Would you like further details on intercepts or have any questions?

Here are some related questions:
1. What are the x-intercepts of the function \( y = 2(x - 1)(x + 2) \)?
2. How would the graph of \( y = 2(x - 1)(x + 2) \) look?
3. How does changing the coefficient affect the y-intercept?
4. How do we find intercepts for more complex polynomial functions?
5. What other points on the graph are easy to calculate manually?

**Tip:** The y-intercept of any function can be found by substituting \( x = 0 \) into the equation and solving for \( y \).

Learn how to find the y-intercept of the quadratic function y = 2(x - 1)(x + 2) with a clear step-by-step solution. This problem demonstrates the concept of intercepts in quadratic functions, suitable for students in Grades 8-10.

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