To find the y-intercept of the quadratic equation $y = x^2 - 3x - 6$, you set $x = 0$, because the y-intercept occurs where the graph crosses the y-axis, and at this point, $x$ is always 0.

So, substitute $x = 0$ into the equation:

$y = (0)^2 - 3(0) - 6$ $y = 0 - 0 - 6$ $y = -6$

Thus, the y-intercept is $y = -6$, or the point $(0, -6)$.

Would you like more details or have any questions?

Here are some related questions:

1. How do you find the x-intercepts of a quadratic equation?
2. What is the vertex of the parabola represented by the equation $y = x^2 - 3x - 6$?
3. How does the coefficient of $x^2$ affect the graph of a quadratic equation?
4. What is the standard form of the quadratic equation $y = x^2 - 3x - 6$?
5. How can you complete the square for the quadratic equation $x^2 - 3x - 6$?

Tip: To find the vertex, you can use the formula $x = -\frac{b}{2a}$ for a quadratic equation $ax^2 + bx + c$.