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The problem asks to find the value of \( y \) such that the points \( A(3, -3, 7) \), \( B(-4, -6, 6) \), and \( C(24, y, 10) \) are collinear (aligned in a straight line).

### Step-by-step solution:

To determine if three points are collinear, the vectors \( \overrightarrow{AB} \) and \( \overrightarrow{AC} \) must be proportional. In other words, \( \overrightarrow{AB} \) and \( \overrightarrow{AC} \) must be linearly dependent, meaning their cross product must be the zero vector.

#### 1. Find the vectors:
- \( \overrightarrow{AB} = B - A = (-4 - 3, -6 - (-3), 6 - 7) = (-7, -3, -1) \)
- \( \overrightarrow{AC} = C - A = (24 - 3, y - (-3), 10 - 7) = (21, y + 3, 3) \)

#### 2. Take the cross product of \( \overrightarrow{AB} \) and \( \overrightarrow{AC} \):
The cross product of two vectors \( \mathbf{u} = (u_1, u_2, u_3) \) and \( \mathbf{v} = (v_1, v_2, v_3) \) is given by:
\[
\mathbf{u} \times \mathbf{v} = (u_2 v_3 - u_3 v_2, u_3 v_1 - u_1 v_3, u_1 v_2 - u_2 v_1)
\]

For \( \overrightarrow{AB} = (-7, -3, -1) \) and \( \overrightarrow{AC} = (21, y + 3, 3) \):
\[
\overrightarrow{AB} \times \overrightarrow{AC} = \left( (-3)(3) - (-1)(y + 3), (-1)(21) - (-7)(3), (-7)(y + 3) - (-3)(21) \right)
\]

This simplifies to:
\[
\overrightarrow{AB} \times \overrightarrow{AC} = (-9 + y + 3, -21 + 21, -7(y + 3) + 63)
\]
\[
= (y - 6, 0, -7y - 21 + 63)
\]
\[
= (y - 6, 0, -7y + 42)
\]

#### 3. Set the cross product equal to the zero vector:
For \( A \), \( B \), and \( C \) to be collinear, the cross product must equal \( (0, 0, 0) \). Therefore, we have the following system of equations:
\[
y - 6 = 0 \quad \text{and} \quad -7y + 42 = 0
\]

From \( y - 6 = 0 \), we get:
\[
y = 6
\]

### Conclusion:
The value of \( y \) for which the points \( A \), \( B \), and \( C \) are collinear is \( y = 6 \).

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Would you like further details or have any questions? Here are five related questions to expand on this concept:

1. How can we verify if a set of three points in 2D are collinear?
2. What does it mean for vectors to be linearly dependent in 3D space?
3. Could the collinearity condition be solved using determinants?
4. How does the cross product help in detecting collinearity of points?
5. What is the geometric interpretation of the cross product?

**Tip:** The cross product is a powerful tool to detect the orientation and collinearity of vectors in 3D space.

Soit un repère orthonormé (O; i⃗, j⃗, k⃗). Soit les points A(3, -3, 7), B(-4, -6, 6) et C(24, y, 10). Donner la valeur de y pour que A, B et C soient alignés.

Learn how to determine the value of y such that the points A(3, -3, 7), B(-4, -6, 6), and C(24, y, 10) are collinear. This solution covers key concepts in vector operations, including cross product and linear dependence, suitable for students in Grades 10-12.

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